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3 years ago

The product of n and 8

Mathematics

1 answer:

Jlenok [28]3 years ago

8 0

Answer:

Step-by-step explanation:

The product of n and 8 means you will multiply n and 8. So, n x 8 is 8n.

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Calculate the following limit:

aleksklad [387]

$\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\$
$\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\$
$=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1
$

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3 years ago

Alvin is running at a rate of 3 meters per second. The meters he runs, m, in s seconds is given by the equation m=3s. Identify t

dem82 [27]

It is 6 because I got the awnser multiple times

4 0

3 years ago

Read 2 more answers

Answer this question pls!!

Dvinal [7]

Answer:

3.5

Step-by-step explanation:

5 0

3 years ago

Solve 3(x - 2) < 18.

Inessa05 [86]

Answer:

3x - 6 < 18

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answer is a

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3 years ago

To be considered for pilot school, 12 students took a spatial reasoning test that resulted in this list of scores. Find the valu

lord [1]

Answer:

the 90th percentile is 145

Step-by-step explanation:

Data provided:

152 121 130 143 122 101 137 98 138 127 145 117

Number of students considered, n = 12

To find:

90th percentile

Now,

Step 1 : Arrange the data in ascending order

98, 101, 117, 121, 122, 127, 130, 137, 138, 143, 145, 152

Step 2 : Compute the position of the 90th percentile

position of the 90th percentile, i = (90% × n)

Thus,

i = 0.90 × 12

i = 10.8

Now,

Step 3 : Since, the index i is not an integer, round up to the nearest integer

i.e i = 11

Therefore,

The 90th percentile is the value in 11th position,

i.e 145

7 0

3 years ago

The product of n and 8​

The product of n and 8