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ANEK [815]
2 years ago
14

If a unit price label has a unit price of 13. 5 cents per ounce, how much is the total price for a 24 ounce package? a. $0. 32 b

. $0. 56 c. $1. 78 d. $3. 24.
Mathematics
1 answer:
notsponge [240]2 years ago
6 0

Answer: d. $3.24

Step-by-step explanation:

13.5 cents = 1 ounce

24 ounce= 13.5x24

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A sign made of solid wood is in the shape of a pyramid. The base is a triangle with a base of 6 feet and a height of 4 feet. The
zaharov [31]

Answer:

$144

Step-by-step explanation:

Volume of the pyramid = 1/3BH

Base area B = 1/2 * 6 * 4

Base area B = 12 ft²

Height H = 4ft

Volume of the pyramid = 12 * 4

Volume of the pyramid = 48ft³

SInce 1 ft³ = $3

48ft³ = x

Cross multiply

x = 3 * 48

x = 144

Hence the cost of the sign is $144

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Pennsylvania has a land mass of 44,816 square miles.What is the land area of Pennsylvania rounded to the nearest hundred?
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The answer would be 44,800 if you want to round the hundreds place
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3 years ago
A farmer is building a fence to enclose a rectangular area against an existing wall, shown in the figure below.
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3 years ago
A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

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3 years ago
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Step-by-step explanation:

The answer is in the picture

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3 years ago
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