solution:
Let the number be ABCDE
>>The second digit is three times the fourth digit<<
So D is 1,2, or 3 and B is 3,6 or 9.
The number is A3C1E, A6C2E, or A9C3E
>>The second digit is ... five more than the fifth digit.<<
That rules out 3 for B, so B is 6 or 9, and D is 2 or 3.
It also tells us that E is 1 or 4, so that B can be 5 more than it.
So the number is A6C21 or A9C34
>>The third digit is ... twice the fourth digit<<
So C is twice D, which is 2 or 3. So C is 4 or 6
So the number is A6421 or A9634
>>The third digit is one-half the first digit
So C is 4 because 6 is too large to be half a digit. And so
A has to be 8 so that C=4 can be half of it.
So the number is 86421.
Answer:
The volume of cone z has the same base area as cylinder y but its height is 3 times the height of cylinder y have the same volume.
Step-by-step explanation:
The volume of a cylinder having base area 'A' and height 'H' is given by V = AH, and the volume of a cone having the same base area as the cylinder i.e. A and height 3 times the height of the cylinder i.e. 3H is given by 
.
So, V = V'
Hence, the volume of cone z has the same base area as cylinder y but its height is 3 times the height of cylinder y have the same volume. (Answer)
Answer:
44.47 cm² (nearest hundredth)
Step-by-step explanation:
Area of ΔABC = 1/2 x base x height
⇒ 21 = 1/2 x 7 x BC
⇒ BC = 6 cm
Pythagoras' Theorem: a² + b² = c²
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
⇒ AB² + BC² = AC²
⇒ 7² + 6² = AC²
⇒ AC² = 85
⇒ AC = √85 cm
Cosine rule to find length AD:
c² = a² + b² - 2 ab cosC
⇒ DC² = AD² + AC² - 2(AD)(AC)cos(DAC)
⇒ 9.2² = AD² + (√85)² - 2(AD)(√85)cos 73°
⇒ AD² - 5.39106...AD + 0.36 = 0
⇒ AD = 5.323442445, 0.06762541414
⇒ AD = 5.323442445
Area of a triangle ADC: (1/2)absinC
(where a and b are adjacent sides and C is the angle between them)
⇒ area = (1/2) × AC × AD × sin(DAC)
⇒ area = (1/2) × √85 × 5.323442445 × sin(73°)
⇒ area =23.4675821... cm²
Area of quadrilateral = area of ΔABC + area of ΔADC
= 21 + 23.4675821...
= 44.47 cm² (nearest hundredth)
I would say the third one. Plug in the x values:
y = -9/3
-9/3 = -3
y = -3
(-9, -3)
The equation is true.
