For y = (x^2 -4)/((x +2)(x^2 -49)) the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7. The horizontal asymptote is y=0.
Well the first part of the table is 7 cause 7x5- 35 x 6 is 42 x 7 49. Second part of the table is 8 x 5 40 x6 is 48 x 7 is 56. once you know this it is easy just to common factor it or just simply add 5 6 or 7 to the numbers already given