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3 years ago

Please click on this picture and explain why I got this answer wrong

Mathematics

1 answer:

butalik [34]3 years ago

3 0

Answer: $79.12

Step-by-step explanation:

We have to find total amount that was paid for dinner

5 people each order was worth $12.80

Therefore, total bill = 12.80*5

= $64

Tax: 7.5%

Therefore, the bill after tax was:

$=64(\frac{100+7.5}{100})\\= 64(1.075)\\$

Bill with tax = $68.8

Gratuity = 15.0% of bill with tax

Therefore, gratuity = 0.15 * 68.8

= $10.32

Ended up paying in total = Gratuity + Bill with tax

= $68.8 + $10.32

= $79.12

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4 years ago

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3m-5m-12=7m-88-5 plz show all work

hammer [34]

3m - 5m - 12 = 7m - 88 - 5

-2m - 12 = 7m - 88 - 5

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4 years ago

A health club charges non-members $12 per day along with an additional charge of $9 per day for a locker. the members pay a year

lorasvet [3.4K]

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3 years ago

The length of a rectangular pool is to be four times its width and a sidewalk 6ft wide will surround the pool. If a total area o

natita [175]

Answer:

52 feet by 13 feet.

Step-by-step explanation:

Given:

The length of a rectangular pool is to be four times its width.

Sidewalk is 6 feet wide will surround the pool.

If a total area of 1600 square feet has been set aside for the area of the pool and the sidewalk.

Question asked:

What are the dimensions of the pool?

Solution:

Let width of a rectangular pool = $x$

Then the length of a rectangular pool will be = $4x$

$Area\ of \ rectnagle= length\times breadth$

$=x\times4x\\ \\ =4x^{2}$

Combined length of pool and the sidewalk = length of pool + width of sidewalk + width of sidewalk

Combined length of pool and the sidewalk = $4x+6+6=4x+12$

Similarly, Combined width of pool and the sidewalk = $x+6+6=x+12$

Combined area of pool and the sidewalk = 1600

$Combined\ lengthh\times Combined\ r=breadth=1600\\ \\ (4x+12)(x+12)=1600\\ \\ 4x(x+12)+12(x+12)=1600\\ \\ 4x^{2} +48x+12x+144=1600\\ \\ 4x^{2} +60x+144=1600$

Subtracting both sides by 144

$4x^{2} +60x=1456\\ \\ 4x^{2} +60x-1456=0\\ \\ Taking\ 4\ as\ common\\ \\ x^{2} +15x-364=0\\ \\ x^{2} +28x-13x-364=0\\ \\ x(x+28)-13(x+28)=0\\ \\ x+28=0,x-13=0\\ \\ x=-28,x=13$