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melomori [17]
2 years ago
9

Find the range for the measure of the third side of a triangle given the measures of two sides. 5 m, 11 m, ?

Mathematics
1 answer:
bixtya [17]2 years ago
4 0

Answer:

d

Step-by-step explanation:

the length of the third side should be less than the sum of other two sides, that is  5+ 11 = 16 and it should be greater than the 5

6 < x < 16

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Elodia [21]
It is b.the residents of the town
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(x+3)^2+5=-28
Sidana [21]

Answer:

Description

Step-by-step explanation:

a. 2 solutions

b. 2 imaginary solutions

c. If the discriminant is positive, then it will have 2 real solutions as the square root of a positive number always equals a positive number. If the discriminant is negative, the quadratic equation will have 2 imaginary solutions, as the square root of a negative number is always imaginary. If the discriminant equals 0, it will have only 1 real solution.

3 0
3 years ago
Solve for x:x-10=44<br>1)34<br>2)15<br>3)54<br>4)-34​
KiRa [710]

Answer:

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :  

                    x-10-(44)=0  

Step by step solution :

Step  1  :

Solving a Single Variable Equation :

1.1      Solve  :    x-54 = 0  

Add  54  to both sides of the equation :  

                     x = 54  

One solution was found :

 x = 54

7 0
3 years ago
Can someone help me with my question
irina1246 [14]
Answer=8.6c+13

Meg earns $5.40 per car and $5 in tips. Given the information, Meg's earnings can be shown in the expression '5.40c+5'

Rich earned 3.20 per car and $8 in tips. Given the information, Rich's earnings can be shown with the expression '3.20c+8'

Now lets put the expressions together to see how much they made all together...

5.40c+5+3.20c+8
add 5.40c and 3.20c
8.60c+5+8
add 5 and 8
8.60c+13
or
8.6c+13




5 0
3 years ago
A researcher wishes to determine whether people with high blood pressure can lower their blood pressure by performing yoga exerc
Anastaziya [24]

Answer:

90% confidence interval for the difference between the two population means

( -23.4166 , -6.5834)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given first sample size n₁ = 100

Given mean of the first sample x₁⁻ = 178

Standard deviation of the sample S₁ = 35

Given second sample size n₂= 100

Given mean of the second sample x₂⁻ = 193

Standard deviation of the sample S₂ = 37

<u><em>Step(ii):-</em></u>

Standard error of two population means

        se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{s^{2} _{1} }{n_{1} }+\frac{s^{2} _{2} }{n_{2} }  }

       se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{(35)^{2}  }{100 }+\frac{(37)^{2}  }{100 }  }

        se(x^{-} _{1} -x^{-} _{2} ) =  5.093

Degrees of freedom

ν  = n₁ +n₂ -2 = 100 +100 -2 = 198

t₀.₁₀ = 1.6526

<u><em>Step(iii):-</em></u>

<u><em> 90% confidence interval for the difference between the two population means</em></u>

<u><em></em></u>(x^{-} _{1} - x^{-} _{2} - t_{\frac{\alpha }{2} }  Se (x^{-} _{1} - x^{-} _{2}) , x^{-} _{1} - x^{-} _{2} + t_{\frac{\alpha }{2} }  Se (x^{-} _{1} - x^{-} _{2})<u><em></em></u>

(178-193 - 1.6526 (5.093) , 178-193 + 1.6526 (5.093)

(-15-8.4166 , -15 + 8.4166)

( -23.4166 , -6.5834)

4 0
3 years ago
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