Janet has 3 cube-shaped boxes. Each box has a side length of 10 inches. What is the minimum amount of wrapping paper needed, in
1 answer:
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Using conversions between odds and probabilities, we have that:
1. A) 4:21
2. 0.952 probability that a bag of flour passes inspection.
3. C) 1:39
4. 41:59.
5. 14:11
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is given by a:b, in which <u>a is the number of successes and b is the number of failures</u>.
Item 1:
- Probability of 0.16, thus, for 100 trials, <u>16 successes and 84 failures</u>, and the odd is:
16:84, which, simplifying by 4, is 4:21.
Item 2:
- Odd of 20:1 means that 20 + 1 = <u>21 trials, there are 20 successes</u>, thus, the probability is:
0.952 probability that a bag of flour passes inspection.
Item 3:
- Probability of 0.025, thus, for 100 trials, <u>2.5 successes and 97.5 failures</u>, and the odd is:
2.5:97.5, which, simplifying by 2.5, is 1:39.
Item 4:
- 59% probability that he will take the longest trail, thus 100 - 59 = 41% probability of him <u>not tanking the longest trail</u>, thus, the odds against him taking the longest trail is 41:59.
Item 5:
- Probability of 0.56, thus, for 100 trials, <u>56 successes and 44 failures</u>, and the odd is:
56:44, which, simplifying by 4, is 14:11.
A similar problem is given at brainly.com/question/21094006
Given:
The ratio of the measures of the three sides of a triangle is .
Its perimeter is 31.4 centimeters
To find:
The shortest side of the triangle.
Solution:
Let the measures of the three sides of a triangle are respectively (in cm).
Its perimeter is 31.4 centimeters.
On further simplification, we get
Divide both sides by 3.
Now, the sides of triangle are
Therefore, the length of the shortest side is 6.978 cm.