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2 years ago

If two sides of a triangle measure 18 centimeters and 22 centimeters what could be the measure of the third side

Mathematics

1 answer:

victus00 [196]2 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

given 2 sides of a triangle then the third side x is in the range

difference of 2 sides < x < sum of 2 sides , that is

22 - 18 < x < 22 + 18

4 < x < 40

3rd side can be any value from 5 to 39

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How to you get the radical form?

Over [174]

Answer:

Note: this answer is kind of long so jump to picture to see a visual process.

In order to find the simplest radical form of a square root, you need prime factorize the number. In order to do this, you take a number and divide it by different prime numbers until all of its factors are now prime. We will use 24 as our example. 24 divided by 2 (which is prime) is 12. 12 divided by 2, is 6. 6 divided by 2 is 3. Therefor, our prime factorization of 24 is 2^3 * 3, which basically means 8 * 3. Then, take take out pairs of the same number and put on the OUTSIDE of the root. However, make sure that it is NEXT to the square root and not inside the mini hook that the square root makes. This means that that number is multiplying the square root of the number. Now, the only pair in this prime factorization is 2, so take two out of the prime factorization and that leaves us with square root 6 times 2, which is the answer.

Also, when taking out pairs, only take one number from the pair (in this case 2) and put it on the outside. If there is another pair, multiply that number by the other number. So if there was a pair of 3 and a pair of 2, take out 1 three and 1 two and multiply them and put on the outside.

Step-by-step explanation:

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2 years ago

Find the length of the segment with endpoints of (3, 2) and (-3, -6).

nevsk [136]

The distance between (3, 2) and (-3, -6) is 10 units

The correct answer is B) 10

Further explanation:

Given points are:

(x1,y1) = (3,2)

(x2,y2)=(-3,-6)

The distance formula is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Putting the values

$d=\sqrt{(-3-3)^2+(-6-2)^2}\\=\sqrt{(-6)^2+(-8)^2} \\=\sqrt{36+64}\\ =\sqrt{100}\\d=10$

The distance between (3, 2) and (-3, -6) is 10 units

Keywords: Magnitude, Distance

Learn more about magnitude at:

#LearnwithBrainly

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sertanlavr [38]

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