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3 years ago

Ahmad runs 7 miles in 80 minutes. At the same rate, how many miles would he run in 64 minutes?

Mathematics

2 answers:

netineya [11]3 years ago

6 0

Answer:
5.6 Miles

Explanation:
7/80=0.0875 Miles per minute
0.0875*64= 5.6 Miles

Julli [10]3 years ago

4 0

First we have to find how long it takes Ahmad to run 1 mile.
So,
A) 80 min will be divided by 7 miles-
80/7 = 11.43 min/ mile
Ahmad runs 1 mile in approximately 11.43min.

B) How long will he run in 64 min?-
Since we know that it takes 11.43min to run 1 mile, we will divide 64 by that 1 mile time.
64/11.43 = 5.6 miles in 64 min.

Our answer is: Ahmad will run 5.6 miles in 64 min.

Another way to solve this, is by cross multiplying:

A)7/80 • x/64 = 448/80x. Now, solve for x by...

B) 448/80 = 5.6
5.6 miles

Hope that helped you understand.

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KengaRu [80]

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8 0

4 years ago

Read 2 more answers

Please help me on this helps!!!

sergeinik [125]

Answer:

2= 95 degrees

3= 25 degrees

1= 60 degrees

5= 25 degrees

4= 95 degrees

Step-by-step explanation:

2) Straight line is 180 degrees so

180-85=95 degrees

3) I got 25 degrees because it's a corresponding angle of X, which is parallel to 25.

1) A triangle is always 180 degrees, 95+25=120 180-120=60

5) Its another corresponding angle to 25

4) Straight line is 180 degrees 60+25=85 180-85=95

Or you could of worked out the bottom 85 and minus it from 180 which will also correspond to 4

5 0

3 years ago

A circle has a diameter of 25cm. How far from the centre of this circle is a chord 16cm long? Draw a picture before you start.

yan [13]

Answer:

The cord is 9.6 cm away from the centre of the circle.

Step-by-step explanation:

See The Image First

The image below shows a picture of everything that’s given, labeled, and drawn in the circle.

Description of the Picture:

You can use the Pythagorean to find the what the distance (the length b) the cord is from the center. You can use the radius as the hypotenuse. The radius is half of the diameter, and the diameter is 25. So the radius is 12.5, which means that 12.5 is the hypotenuse of the triangle (also known as side c). The whole length of the cord is 16cm long, and we can use half of the cord, which is 8cm, for the triangle. So we know two sides already: the hypotenuse (the radius) and the length a of the triangle (half of the length of the cord).

To Solve (variables a, b, and c, are in italics so you don’t get confused):

⇒ Use the formula of the Pythagorean Theorem ( $a^{2}+b^{2}=c^{2}$ ), where b is the length of the distance from the cord to the centre of the circle (what we need to find out), a is the length of the side of the triangle (half of the cord size – 8cm), and c is the hypotenuse (the radius – 12.5cm). So plug the given values of b and c into the formula:

$a^{2}+8^{2}=12.5^{2}$

⇒ Solve for a by simplify:

$a^{2}+64=156.25$

⇒ Subtract 64 from both sides:

$a^{2}=92.25$

⇒ Find the square root of both sides to get a by itself:

$\sqrt{a^{2}}=\sqrt{92.25}$

⇒ Simplify to get:

$a=\sqrt{92.25}$ which convert’s to $a=9.60468635...$ round the answer to the nearest tenth is $a=9.6$

Answer: The cord is 9.6 cm away from the centre of the circle.

I hope you understand and that this helps with your question! :)

8 0

3 years ago

Morris completed the work to solve this problem

LenKa [72]

Can you elaborate so I can see if I can help you

8 0

3 years ago

Twelve different video games showing violence were observed. The duration times of violence were recorded, with the times (sec

docker41 [41]

Answer:

Step-by-step explanation:

Part A :

The requirements (assumption) for testing population mean

1) The Sample are autonomous (not dependent) and normally distributed

2) If the sample size is large ( n >30) then the sampling distribution approaches to normal distribution.

therefore the necessities that are required for testing the claim that the sample is from population with a mean bigger than 80 sec is

D : Either the population is normally distributed or n > 30 or both.

Part B :

To draw normal quantile plot by using R

v <-c(83,13,572,49,0,58,195,41,165,0,2,59)

qqnorm(v)

qqline(v)

From normal qq plot which can be seen from the below attached image, we can see that almost all point on or near the straight line (except one outlier 572).

hence correct answer is

Yes . A normal quantile plot suggests that the sample is from a normally distributed population and there are observation below and above 80.

3 0

3 years ago