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gogolik [260]
3 years ago
14

ASAP help plsss!! Is the following graph proportional? How do you know?

Mathematics
1 answer:
hammer [34]3 years ago
3 0

Answer:

it’s is because it’s linear and going up

Step-by-step explanation:

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−5(1−5k)−4(2k+5) pleas
Kazeer [188]

Answer:

<h2>33k - 25</h2>

Step-by-step explanation:

-5(1 - 5k) - 4(2k + 5)      <em>use distributive property a(b + c) = ab + ac</em>

= (-5)(1) + (-5)(-5k) + (-4)(2k) + (-4)(5)

= -5 + 25k - 8k - 20           <em>combine like terms</em>

= (25k - 8k) + (-5 - 20)

= 33k - 25

5 0
4 years ago
Which property is shown?<br><br> If m∠ABC = m∠CBD, then m∠CBD = m∠ABC
otez555 [7]

ANSWER: symmetric property

hope it helps thanks

brainliest pls

6 0
3 years ago
Read 2 more answers
3x − x − 1 = 15<br> What is x
azamat

Answer: x=8

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x−x−1=15

3x+−x+−1=15

(3x+−x)+(−1)=15(Combine Like Terms)

2x+−1=15

2x−1=15

Step 2: Add 1 to both sides.

2x−1+1=15+1

2x=16

Step 3: Divide both sides by 2.

2x /2 = 16 /2

x=8

4 0
3 years ago
Read 2 more answers
Please help ASAP!!! Find the area of the triangle.
pentagon [3]

Answer:

2.3cm x 4cm =

<h2><u><em>9.2cm²</em></u></h2>

4 0
3 years ago
Two fair dice are rolled. Determine whether the events are dependent or independent. (a) (the first die shows 3) and (the two di
Alborosie

Answer: The events are independent

a) p = 1/36 b) p = 5/216

Step-by-step explanation: both events are independent because the fact that the first die shows it sample space {1, 2, 3, 4, 5, 6} does not stop the second die from showing it own sample space too which is {1, 2, 3, 4, 5, 6}.

The sample space of first die = {1, 2, 3, 4, 5, 6}

The sample space of second die = {1, 2, 3, 4, 5, 6}

The sample space of 2 dice rolled at once is seen as attachment to this answer, find attachment below.

Probability that an event will occur = number of time the event will occur / total number of possible outcome of the event

a)

Probability that first die will show 3 = number of times 3 shows up in the event / total number of outcome of the die = P (3)

P (3) = 1/6

Probability that 2 dice sum up to give 7 = 6/ 36 = 1/6 ( from the sample space for 2 dice attached, it is seen that the sum of 7 comes out 6 times and the total sample space is 36)

P (first die show 3) = 1/6

P ( 2 dice sum to 7) = 1/6

P ( first die show 3) and P ( 2 dice sum to 7) = 1/6 * 1/6 = 1/36.

b)

Probability of the first die showing 4 = P(4) = 1/6

Probability of 2 die sum up to give 8 = 5/36

P ( first die show 8) and P ( 2 die sum up to give 8) = 1/6 * 5/36 = 5/216

7 0
3 years ago
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