If you wanna check the answer apply the foil method
No because 2 is positive, positive numbers are always bigger than negative.
Quadrilateral ABCD is both a rhombus and a rectangle.
The slope is change in "Y" divided by the change in "x"
1-(-3)/2-(-1)
= 4/3
Standard Form
y-y1=m(x-x1)
y-(-3)=4/3(x-(-1)
y+3=4/3x+4/3
y=4/3x-5/3
Rewrite in standard form
-4/3x+y=-5/3
Can't have fractions so multiply by 3 to get rid of the denominator
-4x+3y=5
Divide by -1 to get rid of the negative sign
4x-3y=-5
Answer:
Acute
Step-by-step explanation:
This should be an acute triangle because if this was a right angle, then the three sides should be figured out by the Pythagorean Theorem.
An obtuse angle wouldn't be right either, you need an angle to be over 90.
