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MrMuchimi
2 years ago
6

Select the correct answer.

Mathematics
1 answer:
Afina-wow [57]2 years ago
5 0

Answer:

d)\ \frac{81}{m^{7}}

Step-by-step explanation:

(3m^-4)^3(3m^5)

First, simplify (3m^{-4})^3:

(3m^{-4})^3\\\\3^3*m^{-4*3}\\\\27m^{-12}

27m^{-12}*3m^5\\\\27*3 *m^{-12+5}\\\\81m^{-7}\\\\81*\frac{1}{m^{7}} \\\\\frac{81}{m^{7}}

Hope this helps!

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How much money should be deposited today in an account that earns 7% compounded semiannually so that it will accumulate to $11,0
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Answer:

$8950.37

Step-by-step explanation:

Use the compound amount formula A = P(1 + r/n)^(nt), in which P is the initial amount of money (the principal), r is the interest rate as a decimal fraction, n is the number of times per year that interest is compounded, and t is the number of years.

Here we have A = $11,000, n = 2, r = 0.07 and t = 3, and so:

$11,000 = P(1 + 0.07/2)^(2*3), or

$11,000 = P (1.035)^6

                                           $11,000        $11,000

Solving for P, we get P = ---------------- = ------------- = $8950.37

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Depositing $8950.37 with terms as follows will result in an accumulation of $11,000 after 3 years.

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3 years ago
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Answer:

(a)

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