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3 years ago

10

Identify the range of the function shown in the graph

1 answer:

sergeinik [125]3 years ago

7 0

Answer:

a

Step-by-step explanation:

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What is 1 3/10 times 5

STALIN [3.7K]

2 5/10

Hope this helps!

3 0

4 years ago

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Solve by elimination 3×+11y=4,-2×-6y=0

gizmo_the_mogwai [7]

3x + 11y = 4

2x + 6y = 0

I got
15/2, -5/4

6 0

3 years ago

A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m

zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= $t_{n-1: 1-\alpha/2}$ * ( $\frac{S}{\sqrt{n} }$ )

I've cleared the sample size of the formula

$n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}$

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

$t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025} = t_{4;0.975} =2.776$

$n= (19.62*\frac{2.776 }{8} )^{2}$

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

$t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005} = t_{4;0.995} =4.604$

$n= (19.62*\frac{4.604}{8} )^{2}$

n= 127.49 ≅ 128

I hope it helps!

4 0

4 years ago

Davian is traveling at a constant speed of 85 kilometres per hour. If he is half way through his 510 kilometre trip, how much lo

inna [77]

E.5 hours
All you have to do is subtract 85 from 510 till you have 0

7 0

3 years ago

Read 2 more answers

P(A) = 20%. P(B) = 50%. P(BIA) = P(B). What is P(A and B)?

8_murik_8 [283]

Answer:

P(A and B) = 0.1 = 10%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question, we have that:

$P(A) = 0.2, P(B|A) = 0.5$

What is P(A and B)?

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)*P(A) = 0.5*0.2 = 0.1$

P(A and B) = 0.1 = 10%

8 0

3 years ago