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2 years ago

First Brainliest answer

Mathematics

2 answers:

denis-greek [22]2 years ago

7 0

Step-by-step explanation:

please mark me as brainlest

timurjin [86]2 years ago

6 0

Answer:

$\sf \dfrac{2a+1}{6}$

explanation:

$\hookrightarrow \sf \dfrac{2a-2}{4} -\dfrac{a-4}{6}$

make the denominator same

$\hookrightarrow \sf \dfrac{3(2a-2)}{12} -\dfrac{2(a-4)}{12}$

join both fractions together

$\hookrightarrow \sf \dfrac{3(2a-2-2(a-4))}{12}$

expand the integers

$\hookrightarrow \sf \dfrac{6a-6-2a+8}{12}$

simplify

$\hookrightarrow \sf \dfrac{4a+2}{12}$

Final answer

$\hookrightarrow \sf \dfrac{2a+1}{6}$

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Find the mean of the data.<br><br> 9, 56, 24, 59, 2

timurjin [86]

Answer:

24 because it is the middle number

Step-by-step explanation:

5 0

2 years ago

Simplify x²-49/3x+21

Vera_Pavlovna [14]

First, you factor and simplify (respectively) the numerator and denominator. Your equation becomes:

$\frac{(x-7)(x+7)}{3(x + 7)}$

Notice, there is a (x + 7) on both the top and the bottom. Because of this, they cancel each other out. What is left is your answer:

$\frac{(x-7)}{3}$

3 0

3 years ago

Read 2 more answers

Three teachers handed out math and science textbooks for their classes two teachers had 21 students each and the last teacher ha

Tanya [424]

Answer:

64 textbooks

Step-by-step explanation:

the first two teachers had 21 students each that's 21+21=42

the other teacher had 22 students so apparently all the textbooks handed to the students are,21+21+22=64

8 0

2 years ago

Tell whether each triangle with the given side lengths is a right triangle.

azamat

should be 60 cm if not it's 11

3 0

3 years ago

In a sample of 100 randomly selected concert attendees, the concert organizers find that 11 of them left the show early. The con

3241004551 [841]

Answer:

A) ≈22.4 concert attendees might have left early.

B) 605 attendees might leave early.

Step-by-step explanation:

A) 11/100, or 11%, of the sample left early.

11% of all the concert attendees is (11/100) × 2040 ≅ 22.4

attendees who might have left early.

B) 11% of the total attendance is 11% × 5500 = 605 attendees who might

leave early.

8 0

3 years ago

First Brainliest answer​

First Brainliest answer