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kaheart [24]
2 years ago
9

There are 5 pizza's to be shared among

Mathematics
1 answer:
kupik [55]2 years ago
4 0

Step-by-step explanation:

IF THERE ARE FIVE PIECES TO BE SHARED AND EVERYONE MUST HAVE AN EQUAL SHARE THEN EACH PERSON SHOULD GET HALF A PIZZA WHICH IS 1/2. BETWEEN 0 AND 1 IS WHAT THE FRACTION 1/2 WE BE BETWEEN.

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Solve 3-x/2≥15 <br> A.x ≤ -24 <br> B.x ≤6<br> C.x ≥ -24<br> D.x ≥ -6
krek1111 [17]
What she said hope that helps
7 0
3 years ago
Mr.Martin is giving a math test next period.The test,which is worth 100 points,has 29 problems. Each problem is worth either 5 p
blsea [12.9K]

Answer:

The second option

Step-by-step explanation:

x+y=29

5x+2y=100

then y=29–x

since 5x+2y=100

then 5x+2(29–x)=100

then 5x+58–2x=100

then 3x+58=100

then 3x=100–58

then 3x=42

then x=42/3

then x=14

then y=29–14=15

5 0
4 years ago
Read 2 more answers
PLEASE HELP FAST IM SO CONFUSED AND EXPLAIN PLZZZZ
max2010maxim [7]

Answer:

the answer is 8, the distance between -11 and -3 is 8

Step-by-step explanation:

if you count the between the numbers it's a total of 8

8 0
3 years ago
9) What is the area of a square with a side length of 120 cm?​
mart [117]

Area of square = Side × Side

  • Side of square is 120 Cm.

⇛Area = 120 cm × 120 cm

⇛Area = 14400 cm²

Hence , the area of square is 14400 cm²

8 0
3 years ago
Read 2 more answers
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
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