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1 year ago

The price of a 2-pack shopkin should not be more then 4$. choose an inequality for this situation

Mathematics

1 answer:

lutik1710 [3]1 year ago

5 0

The price of the shopkin should be smaller or or equal

Solution: Should not be more than 4

Answer: <4
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Write an equation in slope-intercept form of the line shown.

7nadin3 [17]

Answer:

$y = 2x - 5$

Step-by-step explanation:

Find the slope using the points, (1, -3) and (3, 1):

$slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 -(-3)}{3 - 1} = \frac{4}{2} = 2$

m = 2

Find the y-intercept (b) by substituting x = 1, y = -3, and m = 2 in $y = mx + b$

$-3 = (2)(1) + b$

$-3 = 2 + b$

Subtract 2 from both sides

$-3 - 2 = 2 + b - 2$

$-5 = b$

$b = -5$

Plug in the value of m and b into the slope-intercept form equation, $y = mx + b$ .

Thus:

$y = 2x +(-5)$

✅ $y = 2x - 5$

5 0

2 years ago

Statistics help please!

Anastasy [175]

The answer would be $9

7 0

3 years ago

A pencil at a stationery store costs $1, and a pen costs $1.50. Stefan spent $7 at the store. He bought a total of 6 items. Whic

LekaFEV [45]

Well, the first one, I have never worked with before so I'm sry but I can't help you with that one. 3y + x = 4 (x=1) 2y - x = 6 (x=8)

4 0

2 years ago

the actual length of wall c is 4 m . to represent wall c noah draw a segment 16cm long what scale is he using explain your reaso

Gnoma [55]

Answer:

1/25

Step-by-step explanation:

1 m = 100 cm

4m x 100 = 400 cm

If it is 16 cm long, then the scale factor is 16/400, which simplifies to 1/25.

7 0

2 years ago

Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$

Accordingly:

$x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}$

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0

3 years ago