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Roman55 [17]
2 years ago
5

Determine is (x-3) is a factor of x^3 - 5x^2 - 4x + 6 using the remainder theorem:

Mathematics
1 answer:
Nutka1998 [239]2 years ago
3 0

Answer:

(x - 3) is not a factor

Step-by-step explanation:

If (x - h) is a factor of f(x) then f(h) = 0

here

f(x) = x³ - 5x² - 4x + 6 , then

f(3) = 3³ - 5(3)² - 4(3) + 6 = 27 - 5(9) - 12 + 6 = 27 - 45 - 6 = - 24

since f(x) ≠ 0 then (x - 3) is not a factor of f(x)

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A salesman's commission rate is 6%. What is the commission from the sale of 36,000 worth of furnaces?
borishaifa [10]

Answer:

2160

Step-by-step explanation:

36000*6/100=2160

6 0
3 years ago
Right triangle FHG is shown. The sine of angle F is 0.53. What is the cosine of Angle h ?
g100num [7]

<u>Given</u>:

Given that FGH is a right triangle. The sine of angle F is 0.53.

We need to determine the cosine of angle H.

<u>Cosine of angle H:</u>

Given that the sine of angle F is 0.53

This can be written as,

sin F=0.53

Applying the trigonometric ratio, we have;

\frac{HG}{FH}=0.53 ----- (1)

Now, we shall determine the value of cosine of angle H.

Let us apply the trigonometric ratio cos \ \theta=\frac{adj}{hyp}, we get;

cos \ H=\frac{HG}{FH} ----- (2)

Substituting the value from equation (1) in equation (2), we get;

cos \ H=0.53

Thus, the cosine of angle H is 0.53

6 0
3 years ago
Explain WHAT WOULD HAPPEN TO motion IF friction DID NDT EXIST.
MA_775_DIABLO [31]

Answer:

If friction did not exist, it would be hard for us to slow down in running, or putting breaks on a car, and more!

If friction did not exist, your car will slide down the road even if you try your best to put the brakes on a car. Friction is a very important force to slow down things that are moving very fast

Step-by-step explanation:

Hoped this helped.

GeniusUser

5 0
3 years ago
Witch is bigger 0.59 or 5.09
Art [367]

Answer:

this is really easy question is 5.09 because 5 is bigger than 0

5 0
3 years ago
Read 2 more answers
At the fast food restaurant, four cheeseburgers and five small fries have a total of 2,310 calories. Three cheeseburgers and two
Svetlanka [38]

<u><em>Answer:</em></u> <em><u>290 calories in a cheeseburger and 230 calories in fries.</u></em>

<em><u>x = calories in a cheeseburger</u></em>

<em><u>y =  calories in an order of small fries</u></em>

<em><u>Four cheeseburgers and five small fries have 2,310 calories. Therefore</u></em>

<em><u>4x + 5y = 2310       (1)</u></em>

<em><u>Three cheeseburgers and two small fries have 1,330 calories. Therefore</u></em>

<em><u>3x + 2y = 1330        (2)</u></em>

<em><u>Equations (1) and (2) model the given situation.</u></em>

<em><u>To solve, multiply (1) by 2, and multiply (2) by 5 to obtain</u></em>

<em><u>  8x + 10y = 4620          (3)</u></em>

<em><u>15x + 10y = 6650          (4)</u></em>

<em><u>Subtract (3) from (4).</u></em>

<em><u>7x = 2030</u></em>

<em><u>x = 290</u></em>

<em><u>From (1), obtain</u></em>

<em><u>5y = 2310 - 4*290 = 1150</u></em>

<em><u>y = 230</u></em>

<em><u> x = 290, y = 23</u></em>

<u><em>Hope this helps!</em></u>

<u><em>:)</em></u>

5 0
3 years ago
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