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balu736 [363]
3 years ago
13

32,8,83,88,58,58,66,11,34,23 calculate the range

Mathematics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

80

Step-by-step explanation:

After spending some time arranging the numbers in order, we get the sequential order as 8, 11, 23, 32, 34, 58, 58, 66, 83, 88.

Next, we need to find the range. The Range of a data set is the difference between the largest and smallest number.

  • Thus, 88 - 8 = 80 as the range.
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Need help solving for x
yawa3891 [41]

Answer:

9.2

Step-by-step explanation:

The given triangle is a right angled triangle. To solve for any of the side length of such triangle, apply the trigonometry ratio formula which can easily be remembered as SOHCAHTOA.

SOH is Sin θ = opposite/hypothenuse,

CAH is Cos θ = Adjacent/hypotenuse

TOA is Tan θ = Opposite/adjacent

Thus, in the right triangle given, we have:

θ = 38°

Opposite side to the given angle = x

Hypotenuse = 15

We're going to use, sin θ = opposite/hypotenuse

Sin(38) = x/15

Multiply both sides by 15 to solve for x

15*sin(38) = x

15*0.616 = x

9.24 = x

<em>x ≈ 9.2 (to nearest tenth)</em>

3 0
3 years ago
I need some help please
Illusion [34]

Answer:

ill answer the answers asap in the comments section

6 0
2 years ago
Find the standard equation of the circle with center (5, -3
Mrac [35]

Answer:

○ C

Explanation:

Accourding to one of the circle equations, \displaystyle (x - h)^2 + (y - k)^2 = r^2,the centre of the circle is represented by \displaystyle (h, k).Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared. Now, in case you did not know how to define the radius, you can choose between either method:

Pythagorean Theorem

\displaystyle a^2 + b^2 = c^2 \\ \\ 6^2 + 8^2 = r^2 \hookrightarrow 36 + 64 = r^2 \hookrightarrow \sqrt{100} = \sqrt{r^2} \\ \\ \boxed{10 = r}

Sinse we are dealing with <em>length</em>, we only desire the NON-NEGATIVE root.

Distanse Equation

\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d \\ \\ \sqrt{[-5 - 3]^2 + [3 + 3]^2} = r \hookrightarrow \sqrt{[-8]^2 + 6^2} = r \hookrightarrow \sqrt{64 + 36} = r; \sqrt{100} = r \\ \\ \boxed{10 = r}

Sinse we are dealing with <em>distanse</em>, we only desire the NON-NEGATIVE root.

I am joyous to assist you at any time.

5 0
2 years ago
Slater’s room is 5 meter long and 3 1/4 meters wide. What is the area of slader’s room?
muminat
I am guessing it is a rectangular room...
so a 5 x 3 1/4 meter room

The area of a rectangle is length * width
A = l * w
plug in the known
A = 5 * 3 1/4
A = 16.25, or 16 1/4

The area of Slater's?, or Slader's?, room is 16.25 meters^2

Hope this helps
5 0
3 years ago
The radius of a circle is 10 m. Find the circumference to the nearest tenth.
Eva8 [605]
The answer is: C≈62.83m
5 0
3 years ago
Read 2 more answers
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