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Minchanka [31]
2 years ago
6

A new fitness center opens with 120 members. Every month the fitness center increases the number of members by 40 members. How m

any members will the fitness center have after being open for 3 months?​
Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
4 0

Answer:

<u>240 members</u>

Step-by-step explanation:

Let y = total and x = no. of months

y = 40x + 120

= 40(3) + 120

= 120 + 120

= <u>240 members</u>

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The following statement describes the number of marbles, n, in a bag. Ten less than eight times the number of marbles is greater
eimsori [14]
The number of marbles is greater than or equal to 12.

The inequality would be:

8n-10≥6n+14

We need to gather all of the variables on one side, so we will subtract 6n from both sides:

8n-10-6n≥6n+14-6n
2n-10≥14

Now we will cancel the 10 by adding it:
2n-10+10≥14+10
2n≥24

Divide both sides by 2:
2n/2 ≥ 24/2
n≥12
6 0
3 years ago
What is the area of 'P'.​
AVprozaik [17]

Answer:

12 square centimetres

Step-by-step explanation:

6*2=12

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4 years ago
Carmen went for a drive in her new car. She drove 437.5 miles in 7 hours. What was her speed?
guajiro [1.7K]

Answer:

62.5 miles per hour

Step-by-step explanation:

Assuming she had the same speed the whole time and never stopped, just divide the miles driven by the time to get miles per hour. 437.5/7 = 62.5, so she drove 62.5 miles per hour.

Hopefully this helps- let me know if you have any questions!

4 0
3 years ago
A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute. A fire hydrant with a green cap provides wa
lapo4ka [179]

Answer:

a) 2b = 3g

b) 3p = b

Step-by-step explanation:

Given:

Fire hydrant with a blue cap, b, provides water at a rate = 1500 gallons per min

Fire hydrant with a green cap, g, provides water at a rate = 1000 gallons per min

Fire hydrant with a purple cap, p, provides water at a rate = ½g = \frac{1}{2}*1000 = 500

a) The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g.

Given flow of blue hydrant, b = 500

Simplifying, we have:

b = 3*500

b = 3 * \frac{1000}{2}

Since the flow rate of green hydrant, g, is 1000, let's replace 1000 with g above.

Therefore,

b = 3 * \frac{g}{2}

b = \frac{3}{2}g

Cross multuply

2b = 3g

The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g is 2b=3g.

b) An equation to relate the flow of water from the purple hydrant, p, to the flow from the blue hydrant, b.

Given flow rate of purple hydrant, p = 500

It could also be re-written as:

\frac{3}{3} * 500

p = \frac{1500}{3}

Since the flow rate of blue hydrant, b, is 1500, let's replace 1500 with b above.

p = \frac{b}{3}

Cross multiply

3p = b

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3 years ago
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Answer:

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