Answer:

Step-by-step explanation:


taking like terms together

taking LCM


taking LCM

splitting the term

splitting the term



we know that

putting this value in above equation

Answer:

Step-by-step explanation:
we are given that A robot is expected to filter pollution out of at least 350 liters of air and water.
Also It filters air at the rate of 50 liters per minute, and it filters water at the rate of 20 liters per minute.
The inequality for number of minutes the robot should filter air (A) and water (W) to meet this expectations can be writte as follows:

Hence the required inequality has been formulated.
Answer:
24
Step-by-step explanation:
Using the definition of factorial
n! = n(n - 1)(n - 2) ....... × 3 × 2 × 1, hence
4! = 4 × 3 × 2 × 1 = 24
I believe the correct answer is thirty six point seven
Answer:

Step-by-step explanation:
Sum of m and one - third of n is :

Product of 3k to the sum is :
