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VLD [36.1K]
2 years ago
15

What is the answer for this question?

Mathematics
2 answers:
hram777 [196]2 years ago
7 0

Answer:

A

Step-by-step explanation:

I just took an assignment on this

Savatey [412]2 years ago
6 0

Answer:

A

Step-by-step explanation:

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The graph highlights two other points on the trend line. Use them to find another equation for the trend line shown for this sca
frutty [35]

Option A:

The equation for the trend line is y = 82x + 998.

Solution:

The points on the line are (2, 1162) and (11, 1900).

Here, x_1=2, y_1=1162, x_2 = 11, y_2=1900

Slope of the line:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

$m=\frac{1900-1162}{11-2}

$m=\frac{738}{9}

m = 82

Point-slope formula:

y-y_{1}=m\left(x-x_{1}\right)

y-1162=82\left(x-2\right)

y-1162=82x-164

Add 1162 on both sides of the equation.

y=82x+998

The equation for the trend line is y = 82x + 998.

Hence Option A is the correct answer.

4 0
3 years ago
What percent of 15 is 5
solmaris [256]

Answer: 33%

Step-by-step explanation: 5/15 simplifies to 1/3 which is 33%

3 0
3 years ago
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Find the value of x.
mestny [16]

Answer:0

Step-by-step explanation:

7 0
3 years ago
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A village experienced 2% population growth, compounded continuously, each year for 10 years. At the end of the 10 years, the pop
pantera1 [17]

Answer:

The initial population at the beginning of the 10 years was 129.

Step-by-step explanation:

The population of the village may be modeled by the following function.

P(t) = P_{0}e^{rt}

In which P is the population after t hours, P_{0} is the initial population and r is the growth rate, in decimal.

In this problem, we have that:

P(10) = 158, r = 0.02.

So

158 = P_{0}e^{0.02*10}

P_{0} = 158*e^{-0.2}

P_{0} = 129

The initial population at the beginning of the 10 years was 129.

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3 years ago
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During a science experiment the temperature of a solution in beaker 1 was 5 degrees below zero. The temperature of a solution in
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The temperature in beaker 2 was 5°
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