We know that
<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
Answer:
Option D my dude
Step-by-step explanation:
it make sense
Answer:
Step-by-step explanation:
<u>Plot the points first:</u>
- Triangle GHJ: G(1,−6), H(2,−5), J(2,1)
- Triangle NOP: N(−6,1), O(−5,2)
Missing Point P is in quadrant 3and its coordinates are (-6, -5) as per symmetry with triangle GHJ.
The answer is A. (-2,-3)
You can use your graphing calculator and go to Matrix and edit. Then plug in the values and next, go to rref and find the values.
Answer:
5pt=2cups
1qt.=2pt
Step-by-step explanation:
I hope that's right
