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Levart [38]
3 years ago
12

Please help!!!!!!! Will mark brainliest

Mathematics
1 answer:
netineya [11]3 years ago
7 0

Answer:

\displaystyle 5

Step-by-step explanation:

\displaystyle ±7 = \sqrt{49} \\ \\ -7 = x + 2\:\:AND\:\:7 = x + 2 \\ \\ -9, 5 = x

Sinse you want the POSITIVE solution, your answer is 5.

I am joyous to assist you at any time.

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∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'. If vertex A is at (-1, 2) and vertex B is at (1, 5), then vert
Paladinen [302]
<span>So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8). </span>
4 0
3 years ago
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(a^2-4a+6)+(3a^2+13a-1) finding the sum of the difference
andreev551 [17]
(a² - 4a + 6) + (3a² + 13 - 1)
= a² + 3a² - 4a + 13a + 6 - 1
= 4a² + 9a + 5

Hope this helps! :)
5 0
4 years ago
Solving quadratic equation using the completing method.<br>(a).x^2+6x+1=0​
irina1246 [14]

Answer:

x = -3 + 2\sqrt2  \ , \ x = -3 - 2\sqrt2

Step-by-step explanation:

x² + 6x + 1 = 0

a = 1 , b = 6 , c = 1

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{-6 \pm \sqrt{36-4}}{2}\\\\x=\frac{-6 \pm \sqrt{32}}{2}\\\\x= \frac{-6 \pm \sqrt{16 \times 2}}{2}\\\\x = \frac{-6 +4\sqrt2 }{2}\\\\x = -3 + 2\sqrt2  \ , \ x = -3 - 2\sqrt2

7 0
3 years ago
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Plz help<br> x−(73+27)=400
Viktor [21]

First solve for parenthesis

73 + 27 = 100

x - 100 = 400

Isolate the x. Add 100 to both sides

x - 100 (+100) = 400 (+100)

x = 400 + 100

x = 500

500 is your answer for x

hope this helps

6 0
4 years ago
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What is the solution to this equation?<br> 3x- x+8+5x-2=10
VashaNatasha [74]
3x -x + 8 + 5x - 2 = 10
3x - x + 5x = 10 -8 +2
7x = 4
x = 7/4
5 0
4 years ago
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