<span>So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8). </span>
(a² - 4a + 6) + (3a² + 13 - 1)
= a² + 3a² - 4a + 13a + 6 - 1
= 4a² + 9a + 5
Hope this helps! :)
Answer:

Step-by-step explanation:
x² + 6x + 1 = 0
a = 1 , b = 6 , c = 1

First solve for parenthesis
73 + 27 = 100
x - 100 = 400
Isolate the x. Add 100 to both sides
x - 100 (+100) = 400 (+100)
x = 400 + 100
x = 500
500 is your answer for x
hope this helps
3x -x + 8 + 5x - 2 = 10
3x - x + 5x = 10 -8 +2
7x = 4
x = 7/4