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Levart [38]
2 years ago
12

Please help!!!!!!! Will mark brainliest

Mathematics
1 answer:
netineya [11]2 years ago
7 0

Answer:

\displaystyle 5

Step-by-step explanation:

\displaystyle ±7 = \sqrt{49} \\ \\ -7 = x + 2\:\:AND\:\:7 = x + 2 \\ \\ -9, 5 = x

Sinse you want the POSITIVE solution, your answer is 5.

I am joyous to assist you at any time.

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Factor this: a^n+a^n+1
NARA [144]

Answer:

1 + 2 a^n

Step-by-step explanation:

4 0
3 years ago
hi umm can some help me understand how to do this you don't need to tell me the answer gust tell me how to do it plesss I will g
gulaghasi [49]
To find the area of a trapezoid, it’s 1/2(base 1 + base 2) x height.
so in this case, base 1 is 16 (add 12+2+2) (the top one) and base 2 is 12 (the bottom one) and the height is 9.
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8 0
3 years ago
What is 105,159 round to the nearest ten thousand is
viva [34]
105,000 would be the correct answer to your problem.
3 0
4 years ago
Find the midpoint of the segment whose endpoints are (8,6) and (-2,-8).
inna [77]

Answer:

\huge{ \fbox{ \sf{ \: ( \: 3 \: ,  \:  - 1 \: )}}}

Step-by-step explanation:

\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}

\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and  \: B(-2,-8) \: be \: (x2 \:, y2)}}

\underline{ \sf{Finding \: the \: midpoint}}

\boxed{ \rm{Midpoint \:  =  \: ( \frac{x1 + x2}{2}  \: ,  \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{8 + ( - 2)}{2}  \: ,  \:  \frac{6 + ( - 8)}{2} )}}

\mapsto { \sf{Midpoint = ( \frac{8 - 2}{2}  \: ,  \:  \frac{6 - 8}{2} }})

\mapsto{ \sf{Midpoint = ( \frac{6}{2}  \: ,  \:  \frac{ - 2}{2}) }}

\mapsto{ \sf{Midpoint = (3 \: \:  ,   - 1)}}

Hope I helped!

Best wishes!! :D

~\sf{TheAnimeGirl}

5 0
3 years ago
PLS HELPPPPP DUE TODAYYYY
Dafna1 [17]

1. y=4x

2. y=-7x-8

3. y=5x+63

4. y=¾x+8

5. y=-3x-½

6. y=1x-3

7. y=2

8. y=-2x+1

9. y=4x+7

wor<u>k for 9</u>

1=4(2)+b

1= 8 +b

-8 -8

7=b

10. y=0

11. y=¾x+6

<u>work </u><u>for </u><u>1</u><u>1</u>

<em>9</em><em> </em><em>=¾(4)+b</em>

<em>=¾(4)+b9</em><em> </em><em>= 3</em><em> </em><em> </em><em> </em><em>+b</em>

<em>+b-3=-3</em>

<em>+b-3=-3 6=</em><em>b</em>

<em>1</em><em>2</em><em>.</em><em> </em><em>sorry </em><em>I </em><em>haven't</em><em> </em><em>done </em><em>thai </em><em>one </em><em>in </em><em>a </em><em>while.</em>

<em>I </em><em>was </em><em>too </em><em>lazy </em><em>to </em><em>include</em><em> </em><em>the </em><em>work </em><em>for </em><em>the </em><em>first </em><em>couple</em><em> </em><em>of </em><em>answers</em><em> </em><em>although</em><em> </em><em>I </em><em>recommend</em><em>.</em><em> </em>

<em>M</em>

<em>A</em>

<em>T</em>

<em>H</em>

<em>W</em>

<em>A</em>

<em>Y</em>

<em>they </em><em>include</em><em> </em><em>work </em><em>with </em><em>ads</em>

6 0
3 years ago
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