Question

For triangle ABC, which one is equal to sine A? Group of answer choices sine B tangent C cosine C cosine B

Answer 1

Answer:

sin(A) = cos(C)

Step-by-step explanation:

Trig ratios:

$\mathsf{\sin(\theta)=\dfrac{O}{H} \ \ \ \cos(\theta)=\dfrac{A}{H} \ \ \ \tan(\theta)=\dfrac{O}{A}}$

(where $\theta$ is the angle, O is the side opposite the angle, A is the side adjacent to the angle, H is the hypotenuse, of a right triangle)

$\mathsf{\sin(A)=\dfrac{BC}{AC}}$

$\mathsf{\cos(C)=\dfrac{BC}{AC}}$

Therefore, sin(A) = cos(C)