Solve for r in the first equation:
3(r+300) = 6
Use the distributive property:
3r + 900 = 6
Subtract 900 from both sides:
3r = -894
Divide both sides by 3:
r = -894 / 3
r = -298
Now you have r, replace r in the second equation and solve:
r +300 -2 =
-298 + 300 - 2 = 0
The answer is 0.
Answer:
a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:
b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence
Step-by-step explanation:
Triangle AGB is congruent to Triangle CGB.
Answer:
The coordinates are (0,b)
Step-by-step explanation:
Here, we want to find the coordinates of the midpoint F
as we can see, F is between A and B
we proceed to use the midpoint formula
The midpoint formula is;
(x,y) = (x1 + x2)/2, (y1 + y2)/2
(x1,y1) = (-3a, b)
(x2,y2) = (3a, b)
The substitution of these values will thus yield;
(-3a + 3a)/2, (b + b)/2
= (0/2), (2b/2)
= (0, b)
