Calculate the volume. Round your answers to the nearest tenth if necessary.

Which calculation will give the total surface area of the solid figure?

KengaRu [80]

Answer:

Step-by-step explanation:

6.

3 0

3 years ago

Read 2 more answers

Apple pies cost $5.75 each and cherry pies cost $6.50 each.Susan bought nine pies for a total cost of $53.25.There is no tax cha

Tanzania [10]

5.75a + 6.5c = 53.25

a + c = 9

c = 9 - a

5.75a + 58.5 - 6.5a = 53.25

5.25 = 0.75a

a = 7

7 + c = 9

c = 2

she bought 7 apple pies

please give brainliest

7 0

2 years ago

Is the statement below always,sometimes,or never true? Give at least two examples to support your reasoning. The LCM of two numb

Natali5045456 [20]

Answer:

True for Co-Prime Numbers
False for Non Co-Prime Numbers

Step-by-step explanation:

STATEMENT: The LCM of two numbers is the product of the two numbers.

This statement is not true except if the two numbers are co-prime numbers.

Two integers a and b are said to be co-prime if the only positive integer that divides both of them is 1.

Example:

Given the numbers 4 and 7, the only integer that divides them is 1, therefore they are co-prime numbers and their LCM is their product 28.

However, consider the number 4 and 8. 1,2 and 4 divides both numbers, they are not co-prime, Their LCM is 8 which is not the product of the numbers.

3 0

3 years ago

8 ÷ (-2) = -2 × (-3) =

Vinvika [58]

Top answer is -4 because when you divide by a negative your answer will come out negative and bottom answer is 6 because when you multiply two negatives it turns into a positive

3 0

3 years ago

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Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value $t_{0}$ falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by $2P(T$ 0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}$ , i.e.,

$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

where $t_{0.025}$ is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

$-0.03\pm(2.0167)(0.012459)(0.3)$ , i.e.,

(-0.0225, -0.0375)

8 0

3 years ago