Question

Tara has two bags of M&M’s. The first bag contains 6 red, 5 blue, and 4 green M&M’s. The second bag contains 3 red, 2 blue, and 4 green M&M’s. Tara will select one M&M from each bag. What is the probability that Tara will select a blue M&M from each bag?

Answer 1

Answer:

29.6667%

Step-by-step explanation:

In first bag there is 15 M&M's ANd second bag has a total of 9 M&M's so that means there are a total of 24 M&M's.

In the first bag there is 5 blue M&M's and in the second bag there is a total of 2 blue M&M's so there is a total of 7 blue M&M's all together.

so there are 7/24 M&M's ( what were going to do it convert it into percents.

To do this were going to use these steps.

1. were going to divided the number of blue M&M's by the total of M&M's all together so 7 divided by 24=?
2. And then next we are going to multiply the result by 100 which=?

Calculations

7 divided by 24=0.291666.

Ok so now what is 0.291666 x 100=?

0.291666 x 100=29.6667 and there is our final answer.

Hope it helps have awesome day:)