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Stella [2.4K]
2 years ago
9

Help asap please!!!! due tonight!!! brainliest for fastest right answer!!! xx​

Mathematics
1 answer:
Serga [27]2 years ago
3 0

Answer:

Step-by-step explanation:

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One way to increase acceleration is by
Arlecino [84]

Answer:

D. Increasing both force and mass equally

Step-by-step explanation:

I had a question just like this and I answered it correctly, so I hope this helps.

4 0
3 years ago
If x =2/3, what is the value of the following expression? X^3 x 3 divided by 2/9 + 9x - 7-6x
Damm [24]
This is a basic algebraic equation

And will be using PEMDAS to solve

P: Parentheses
E: exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction

If you are unaware of PEMDAS this is the order at which you solve algebraic equation. So start from “P” and end with “S”


X= 2/3

2/3^3 Times 3 Divided by 2/9 + 9(2/3) - 7 - 6(2/3)

Now, personal I’d choose to convert fractions to decimals to simplify solving the equation. I doubt this is the only way to solve for the equation but I find this is the easiest

To convert a fraction to decimal you divide the numerator by the denominator.

So 2/3 is 0.666667
And
That means 2/9 is 0.222222

0.666667^3*3/0.222222+9(0.666667)-7-6(0.666667)

Making you answer roughly -0.999989

Hope this helps, but I’m not sure if this is completely right or not
3 0
3 years ago
Which ordered pair is a solution of the system of equations shown in the graph below?
Ad libitum [116K]

Answer: A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
Please help! i reward brainliest <br> plz no silly answers
FrozenT [24]

Answer:

With 4 times the number of machines, it would take 8 hours

Step-by-step explanation:

8 0
2 years ago
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