Question

Find a formula for the quadratic function whose graph has vertex (2,4) and y-intercept -3.

Answer 1

Answer:

$y=-\frac{7}{4}x^2+7x-3$

Step-by-step explanation:

y - 4 = C(x - 2)²

y-intercept = -3, so x = 0, y = -3

-3 - 4 = C(2)²

so C = -7/4

$y = -\frac{7}{4}(x-2)^2+4=-\frac{7}{4}(x^2-4x+4)+4=-\frac{7}{4}x^2+7x-7+4\\y=-\frac{7}{4}x^2+7x-3$