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2 years ago

13

What is the value of

%3A%20if%20%5C%3A%20p%20%3D%206%20%5C%3A%20and%20%5C%3A%20q%20%3D%205" id="TexFormula1" title=" \sqrt{(p { }^{2} } - 4q) \: if \: p = 6 \: and \: q = 5" alt=" \sqrt{(p { }^{2} } - 4q) \: if \: p = 6 \: and \: q = 5" align="absmiddle" class="latex-formula">

2 answers:

damaskus [11]2 years ago

7 0

Answer:

<u>4</u>

Step-by-step explanation:

<u>Given :-</u>

p = 6

q = 5

√(p² - 4q)

<u>To Find :-</u>

Value of expression after evaluation

<u>Solving :-</u>

= √(6)² - 4(5)

= √36 - 20

= √16

= 4

<u>Solution :-</u>

<u>4</u>

Lynna [10]2 years ago

7 0

Answer:

4

Step-by-step explanation:

<u>Solving</u>

Step 1: Plug in the values of p and q.

$\sqrt{(6^2-4*5)}$

Step 2: Solve exponents.

$\sqrt{(6*6-4*5)}$
$\sqrt{(36-4*5)}$

Step 3: Solve multiplication.

$\sqrt{(36-20)}$

Step 4: Subtract 20 from 36.

$\sqrt{16}$

Step 5: Solve square root.

$\sqrt{16} = 4$

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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A right rectangular prism's edge lengths are 10.5 inches, 5 inches, and 2 inches. How many unit cubes with edge lengths of .5 in

Ede4ka [16]

Answer:

840 cubes

Step-by-step explanation:

First we need to find the volume of each one:

Rectangular prism: Volume = 10.5 * 5 * 2 = 105 in3

Cube: Volume = 0.5 * 0.5 * 0.5 = 0.125 in3

Now, to find how many cubes can fit inside the prism, we just need to divide the volume of the prism by the volume of the cube:

Number of cubes = 105 / 0.125 = 840 cubes

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3 years ago

The lengths of the sides of a triangle are in the extended ratio 7: 9 : 10. The perimeter of the triangle is 52 cm. What are t

Pavel [41]

Answer:

14 cm, 18 cm, 20 cm

Step-by-step explanation:

7x + 9x + 10x = 26x

equation: 26x = 52

divide each side by 26: x = 2

7 * 2 = 14

9 * 2 = 18

10 * 2 = 20

check if answer is right: 14 + 20 + 18 = 52

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3 years ago

When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra

Sergeu [11.5K]

Answer:

$r=\sqrt{10}\text{ m}$

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

$V=\pi r^2h$ , where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be $h = 0.7$ meters at $V=22\text{ m}^3$ .

Upon substituting these values in above formula, we will get:

$22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})$

$22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}$

$\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2$

$r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}$

$r^2=10\text{ m}^2$

Now, we will take positive square root of both sides as radius cannot be negative.

$\sqrt{r^2}=\sqrt{10\text{ m}^2}$

$r=\sqrt{10}\text{ m}$

Therefore, radius of tank would be approximately square root of 10 m.

5 0

3 years ago

In a population distribution, a score of x=57 corresponds to z=-0.25 and a score of x=87 corresponds to z=1.25. Find the mean an

Serggg [28]

Here is dependence between scores and x-values:

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$-0.25=\dfrac{57-\mu}{\sigma}.$

2. When i=2, $Z_2=1.25,\ X_2=87,$ then

$1.25=\dfrac{87-\mu}{\sigma}.$

Now solve the system of equations:

$\left\{\begin{array}{l}-0.25=\dfrac{57-\mu}{\sigma}\\ \\1.25=\dfrac{87-\mu}{\sigma}.\end{array}\right.$

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Subtract first equation from the second:

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Then

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