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aksik [14]
2 years ago
7

Look at the map above. What are the two largest climate regions in Canada?

Geography
1 answer:
tatyana61 [14]2 years ago
4 0
The answer to you’re question is C. Humid subtropical and humid continental.
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Imagine that you have obtained spectra for several galaxies and have measured the observed wavelength of a hydrogen emission lin
Lerok [7]

Answer:

A. z (galaxy 1) = -0.00515, z (galaxy 2) = -0.01707, z (galaxy 3) = -0.04008

B. v (galaxy 1) = -0.00517c, v (galaxy 2) = -0.01707c, v (galaxy 3) = -0.0401c

C. d (galaxy 1) = -21 Mpc,d (galaxy 2) = -69.4 Mpc, d (galaxy 3) = -163 Mpc

Explanation:

We begin by listing out the parameters we were given:

λ (obsv) = 656.3 nm, λ (emit 1) = 659.7 nm, λ (emit 2) = 667.7 nm,

λ (emit 3) = 683.7 nm

A) Using the Redshift formula, we have:

z = [λ (obsv) - λ (emit)]  ÷ λ (emit)

For galaxy 1:

z = [λ (obsv) - λ (emit 1)]  ÷ λ (emit 1)

z = (656.3 - 659.7) ÷ 659.7 = -0.00515

z = -<u>0.00515</u>

For galaxy 2:

z = [λ (obsv) - λ (emit 2)]  ÷ λ (emit 2)

z = (656.3 - 667.7) ÷ 667.7 = -0.01707

z = -<u>0.01707</u>

For galaxy 3:

z = [λ (obsv) - λ (emit 3)]  ÷ λ (emit 3)

z = (656.3 - 683.7) ÷ 683.7 = -0.04008

z = -<u>0.04008</u>

B) Using the Doppler formula, we have:

(Δλ ÷ λ) = v ÷ c

v = c * (Δλ ÷ λ)

but, z = (Δλ ÷ λ)

⇒ v = c * z

speed of light (c) = 3 x 10^{8} m/s

For galaxy 1:

v = c * z

Substitute z into the equation calculated from A) above

v =  3 x 10^{8} * (-0.00515)

v = -1.55 x 10^{6} m/s

v = -<u>0.00517c</u>

For galaxy 2:

v = c * z

Substitute z into the equation calculated from A) above

v =  3 x 10^{8} * (-0.01707)

v = -5.12 x 10^{6} m/s

v = -<u>0.01707c</u>

For galaxy 3:

v = c * z

Substitute z into the equation calculated from A) above

v =  3 x 10^{8} * (-0.04008)

v = -12.03 x 10^{6} m/s

v = -<u>0.0401c</u>

N.B: the negative value of velocity connotes that the galaxies are moving away from us (not towards us)

C) Using Hubbleʹs law, we have:

v = H · d

where:

v = velocity of a galaxy (km/s), d = distance (Mpc),

H = Hubble's constant (km/s/Mpc) = 73.8 km/sec

d = v ÷ H

We use the velocities calculated in B) above

For galaxy 1:

v = -1.55 x 10^{3} km/s

d = -1.55 x 10^{3} ÷ 73.8

d = -<u>21 Mpc </u>

For galaxy 2:

v = -5.12 x 10^{3} km/s

d = -5.12 x 10^{3} ÷ 73.8

d = -<u>69.4 Mpc </u>

For galaxy 3:

v = -12.03 x 10^{3} km/s

d = -12.03 x 10^{3} ÷ 73.8

d = -<u>163 Mpc</u>

N.B: distance cannot be a negative value

4 0
3 years ago
How does carbon move between the atmosphere, hydrosphere, biosphere, and geosphere?
Zarrin [17]

Answer:

See it in the explanation

Explanation:

1) Carbon moves from atmosphere to hydrosphere and biosphere in the process of photosynthesis and to lithosphere by deposition of dead bodies while from hydrosphere and biosphere, carbon can be move in the process of respiration by animals.

2) During respiration process which takes place in plants in which carbondioxide is released and by eating carbon containing food by animals. By decomposing the food, carbon is releases in the form of carbondioxide.

3) Carbon can be used by the marine plants in the process of photosynthesis and during the process of diffusion, carbon is also dissolve in water bodies.

4) When the plants and animals die, the carbon which is present inside their body is buried in the soil present at the bottom of the ocean and the shells and corels of some animals also contain carbon which is soon be the part of the lithosphere when they die.

5) After the decomposition of seashell, carbondioxide is produced because shells are made up of calcium carbonate.

7 0
3 years ago
Write active or passive
MissTica
1 passive 2 passive 3 active
6 0
3 years ago
Why does Coca-Cola have bottling plants all over the world and not just one major plant?
Alexandra [31]

Answer:

idk thats a good question

Explanation:

5 0
3 years ago
Read 2 more answers
Which “main” layer of the Earth contains the least mass? please explain
Mamont248 [21]

Answer:

The crust because is the thinnest layer

6 0
2 years ago
Read 2 more answers
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