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vovikov84 [41]
2 years ago
15

Help please(geometry math)

Mathematics
1 answer:
Liula [17]2 years ago
8 0

Answer:

No solution

Step-by-step explanation:

By bisector theorem: the relative lengths of the two segments that a triangle's side is divided into by a line that bisects the opposite angle. It equates their relative lengths to the relative lengths of the other two sides of the triangle

y/8 = 8/2

y = 32 .... sum of the length of 2 sides of triangle must be larger than the 3rd side, 8+2+8 = 18 < 32

y can only has a value < 18

If we use Law of Sines also get y = 32 ... not forming a triangle

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one tank is filling at a rate of 3/4 per gallon per 2/3 minute .a second tank is at a 5/8 gallon per 1 half gallon per 1/2 minut
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so... you tells us, which filling rate is the bigger and thus faster one?

6 0
3 years ago
Use trigonometric substitution to verify that
photoshop1234 [79]
T = 0
=> Q = 0
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=> Q = arcsin(x/a)
 rest it just simple integration of trigonometric function
8 0
3 years ago
Broderick had $420 in his checking account. He made 6 deposits of $35.50 each. He needs to write 4 checks for $310.75 each.How m
kvasek [131]
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3 0
3 years ago
A 50-gallon rain barrel is filled to capacity. It drains at a rate of 10 gallons per minute. Write an equation to show how much
makvit [3.9K]

Answer:

The quantity of water drain after x min is 50 (0.9)^{x}  

Step-by-step explanation:

Given as :

Total capacity of rain barrel = 50 gallon

The rate of drain = 10 gallon per minutes

Let The quantity of water drain after x min = y

Now, according to question

The quantity of water drain after x min = Initial quantity of water ×  (1-\dfrac{\textrm rate}{100})^{\textrm time}

I.e The quantity of water drain after x min = 50 gallon ×  (1-\dfrac{\textrm 10}{100})^{\textrm x}

or,  The quantity of water drain after x min = 50 gallon × (0.9)^{x}

Hence the quantity of water drain after x min is 50 (0.9)^{x}  Answer

4 0
3 years ago
Read 2 more answers
Can someone please tell me the answer on this.
marishachu [46]

Answer: x = 31

Step-By-Step:

<u>To Find x:</u>

<u />\left(2x+20\right)+\left(x+10\right)+\left(2x-5\right)=180 (Angle Sum Property Of Triangles)

(Remove the brackets)

<u />2x+20+x+10+2x-5=18<u />

(Group Accordingly)

<u />2x+x+2x+20+10-5=180<u />

= 5x+20+10-5=180

= 5x\:+\:25 =180

= 5x= 180 - 25

= 5x = 155

= x=\frac{155}{5}

= 31

<u>Therefore</u> x = 31

So,

Angle A = x + 10 = 31 + 10 = 41

Angle B = 2*x + 20 = 2*31 + 20 = 82

Angle C = 2*x - 5 = 62 - 5 = 57

5 0
3 years ago
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