Step-by-step explanation:
there might be some information missing as the problem definition seems to be cut off.
but from what I can see I understand we have to find how many different groups of 3 people we could make out of 5 people in total.
that means the sequence does not matter, right ?
(Brenda, Miguel, Ronne) would be the same as
(Ronne, Brenda, Miguel).
and we can't pick a person twice or thrice for the same group (otherwise we would not make a group, but simply "pick" lottery tickets, where each ticket can win multiple prices).
if that all is the case, then we need to calculate the combinations of 3 elements out of 5 :
5! / (3! × (5-3)!) = 5! / (3! × 2!) = 5×4/2 = 5×2 = 10
we can make 10 different groups of 3 people out of 5 people.
