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2 years ago

Can someone help me with this

Mathematics

1 answer:

jolli1 [7]2 years ago

5 0

Answer:

4 sides

Step-by-step explanation:

A lot of math is about pattern matching. Here, you're asked if sides are the same length (one side matches another), if there are right angles (square corners), and if the number of angles or sides is 4.

You might make the observations ...

pink: 2 pairs of parallel sides that are the same length (4 sides). Adjacent sides are different length.

orange: all 4 sides are congruent and at right angles

blue: 2 pairs of parallel sides that are the same length (4 sides). Adjacent sides are different length.

green: 2 pairs of parallel sides that are the same length--4 sides and 4 right angles. Adjacent sides are different length.

The only feature in common is "4 sides."

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adelina 88 [10]

The answer is 2.041*10 to the 6th power

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4 years ago

A bag contains 5 red beads, 3 green beads and 2 blue beads (10 total). If beads are picked from the bag without

OLga [1]

Answer:

2/9 or .22 repeating

Step-by-step explanation:

P(red,red) = $\frac{5}{10}$ · $\frac{4}{9}$ = 2/9 reduced form

4 0

3 years ago

Could someone possibly help me with this question?

MrRa [10]

Answer:

See explanation

Step-by-step explanation:

Statement Reason

1. the diagram shows segment AC with point B on this segment, then

$AB+BC=AC$ Segment addition postulate

2. Given $AB=2x,\ BC=6x+8,\ AC=32,$ then

$2x+6x+8=32$ Substitution property

3. Simplify the equation as follows

$8x+8=32$ Combine like terms

4. Subtract 8 from both sides

$8x+8-8=32-8\\ \\8x=24$ Subtraction property of equality

5. Divide by 8:

$x=3$ Division property of equality

8 0

3 years ago

ANSWER RIGHT OR I WILL REPORT YOU. FAST BRAINLIST

Klio2033 [76]

Answer:

28 i tryed an this is wat i got so

Step-by-step explanation:

7 0

3 years ago

The corner points for the bounded feasible region determined by the system of inequalities: 5x + 2y < 40 x + 3Y < 21 x,y &

iVinArrow [24]

Answer:

Step-by-step explanation:

Given

5x+2y<40

x+3y<21

These two lines intersect at (6,5)

we have to maximize 10x+5y

Four corner points are

(0,0) $\Rightarrow$ 10(0)+5(0)=0

(0,7) $\Rightarrow$ 10(0)+5(7)=35

(6,5) $\Rightarrow$ 10(6)+5(5)=85

(8,0) $\Rightarrow$ 10(8)+5(0)=80

At x=6 and y=5 optimal solution is obtained.

5 0

3 years ago