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ArbitrLikvidat [17]
2 years ago
8

Please help it’s due tonight!!

Mathematics
1 answer:
Alina [70]2 years ago
6 0

Answer:

4: 1.33 ft.

5: 516.14322017669 mm

6:

7:

8: 7 cm

9: 27314.29921175 mm

10: 112 ft.

Step-by-step explanation:

not sure about 6 and 7

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Find the equation of the line I in the following picture. The shapes under the lines are squares
julia-pushkina [17]
If you look carefully at the graph, you may see that the slope of the line is
          3-4           -1
---------------- = ------ = m
         7-4             3

thus, you have the slope of the line and two points on the line.  Suppose we
choose the point (4,4) and subst. the known slope and the coordinates of this point into the point-slope formula for the eqn of a str line:

y-y1 = m (x-x1)

y-4 = (-1/3)(x-4)

This is the desired equation.  You could, if you wished, change this into slope-intercept form.
5 0
3 years ago
A old computer model that cost $599(whole) is marked down 5%. How much money will the customer save (what is the discount only)?
Butoxors [25]

Answer:

The discount is 29.95

Step-by-step explanation:

599 x .05= 29.95

8 0
3 years ago
Read 2 more answers
In triangle ABC, what is the length of side bif B = 48°, C= 81°, and c= 25?
Mashcka [7]

Answer: The correct option is D: Is alloyed with carbon and chromium to make stainless steel.

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7 0
3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Bas_tet [7]

Answer:

22.05

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
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