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lina2011 [118]
2 years ago
5

Can somebody help me

Mathematics
1 answer:
iogann1982 [59]2 years ago
7 0

Answer:

a) yes

b) yes

c) yes

d) no

e) no

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Cos(x + y) + cos(x − y) = 2 cos(x) cos(y)
Alex17521 [72]
   
\texttt{We use formula: }~~~  \boxed{\cos(x\pm y) = \cos (x) \cos (y) ~\mp ~\sin (x) \sin (y)}\\\\
\cos(x + y) + \cos(x - y) =\\\\
= \underbrace{\cos (x) \cos (y) -\sin (x) \sin (y)}_{\cos(x + y) } +\underbrace{\cos (x) \cos (y) +\sin (x) \sin (y)}_{\cos(x - y)} =\\\\
=\cos (x) \cos (y)+\cos (x) \cos (y)-\sin (x) \sin (y)+\sin (x) \sin (y)=\\\\
=\cos (x) \cos (y)(1+1) + \sin (x) \sin (y)(-1+1) = \\\\
=2\cos (x) \cos (y) + 0\sin (x) \sin (y) = \boxed{\boxed{2\cos (x) \cos (y)}}



6 0
2 years ago
Read 2 more answers
Write the equation of a circle with a center at (1,-9) and a radius of 12
Andre45 [30]

The equation of the circle is (x - 1)^2 +(y + 9)^2 = 144

<h3>How to determine the circle equation?</h3>

The given parameters are:

Center, (a,b) = (1, -9)

Radius, r = 12

The circle equation is calculated as:

(x - a)^2 + (y- b)^2 = r^2

This gives

(x - 1)^2 +(y + 9)^2 = 12^2

Evaluate the exponent

(x - 1)^2 +(y + 9)^2 = 144

Hence, the equation of the circle is (x - 1)^2 +(y + 9)^2 = 144

Read more about circle equations at:

brainly.com/question/10618691

#SPJ1

8 0
1 year ago
A lamp manufacturer uses 714 m of electrical cord each week. The cord comes on spools that hold 12 m each.
RoseWind [281]
I meant to put the number 19
3 0
2 years ago
Ravi drove 648 miles in 9 hours. At the same rate,how long would it take him to drive 792 miles ?
anygoal [31]

Answer:

11 hours

Step-by-step explanation:648/9=72 miles per hour

792/72=11

4 0
3 years ago
Read 2 more answers
A student's work to solve an equation is shown.
aliya0001 [1]

9514 1404 393

Answer:

  • incorrectly
  • one solution

Step-by-step explanation:

The third line of the solution is incorrect. It should be ...

  5x +2 = -5x +2

Then the one solution can be found:

  10x = 0 . . . . . . . . . add 5x-2 to both sides

  x = 0

4 0
2 years ago
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