Question

Find the solution set by using the method of equating the coefficients.

Answer 1

$\left \{ {{2x-3y=6} \atop {3x+5y=0}} \right. \\ \left \{ {{2x=6+3y} \atop {3x+5y=0}} \right. \\ \\ x=3+1,5y \\ 3(3+1,5y)+5y=0 \\ 9+ \frac{9}{2} y+5y=0 \\ \frac{19}{2} y=-9 \\ y=- \frac{18}{19} \\ x=3+1,5*(-\frac{18}{19} )= \frac{30}{19}$