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2 years ago

10

The half-life of a radioactive kind of praseodymium is 17 minutes. If you start with 56 grams of it, how much will be left after

34 minutes? grams Submit

1 answer:

lana66690 [7]2 years ago

6 0

Answer:

14 grams?

Step-by-step explanation:

56/2=28 28/2=14

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pogonyaev

Step-by-step explanation:

Actual graph for this problem is attached below

m∠TUV = 167°

m∠TUL = (x + 11)°

m∠LUV = (11x)°

m∠TUV= m∠TUL+ m∠LUV

now plug in the angles for each

m∠TUV= m∠TUL+ m∠LUV

$167= x+11 +11x$

solve the equation for x

$167= x+11 +11x\\167=11 +12x$

Subtract 11 from both sides

$156=12x$

divide both sides by 12

x=13

m∠TUL = (x + 11)°

m∠TUL = (13+ 11)° = (24)°

answer:

24°

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Please explain the problem to me step by step

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<h3>Solution:</h3>

$\frac{4y}{9} - \frac{2y}{3} = 10 \\ = > \frac{4y - 6y}{9} = 10 \\ = > \frac{ - 2y}{9} = 10 \\ = > y = 10 \times \frac{9}{ - 2} \\ = > y = - 5 \times 9 \\ = > y = - 45$

<h3>Answer:</h3>

-45

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