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sashaice [31]
2 years ago
8

The perimeter of a rectangle is 84. If the length is 2 more than three times the width, what are the dimensions of the rectangle

? Show how you represent the unknown and create the equation. *
Mathematics
1 answer:
Marina86 [1]2 years ago
5 0

The perimeter solved shows that the dimensions of the rectangle are 32 and 10.

<h3>How to calculate the perimeter</h3>

Let the width be w

Length = 3w + 2

Perimeter = 2(length + width)

Perimeter = 2(3w + 2) + 2w

6w + 4 + 2w = 84

8w + 4 = 84

8w = 84 - 4

w = 80/8

w = 10

Length = 3w + 2

Length = 3(10) + 2

Length = 32

The dimensions of the rectangle are 32 and 10.

Learn more about perimeter on:

brainly.com/question/19819849

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Answer:

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Harlamova29_29 [7]
Answer: 36 units squared.


Explanation:
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| 0.5{x1(y2-y3) + x2(y3-y1) + x3(y1-y2)} |

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x1 =0, y1=0

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7 0
3 years ago
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Harlamova29_29 [7]

Answer:  Missing parts are,

In first blank,  AD\cong DC,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

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BD\cong BD ( reflexive)

Thus, By SAS ( side angle side )postulate,

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So, by CPCTC( Corresponding parts of congruent triangles are congruent)

AB\cong CB

Now, By definition of congruent segment,

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By definition of equidistant,

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likoan [24]
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or
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4 0
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