The perimeter solved shows that the dimensions of the rectangle are 32 and 10.
<h3>How to calculate the perimeter</h3>
Let the width be w
Length = 3w + 2
Perimeter = 2(length + width)
Perimeter = 2(3w + 2) + 2w
6w + 4 + 2w = 84
8w + 4 = 84
8w = 84 - 4
w = 80/8
w = 10
Length = 3w + 2
Length = 3(10) + 2
Length = 32
The dimensions of the rectangle are 32 and 10.
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