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2 years ago

I'm gonna cry someone please help.

Mathematics

1 answer:

Nostrana [21]2 years ago

4 0

Answer:

Median for a: 50 because it is in the middle of the points

Median for b: 35 because it is in the middle of the points.

Step-by-step explanation:

What i do is i write all the numbers out as shown in graph and cross one out on both sides untill there is one left.

IQR A: 15

IQR B: 15

Find the 25 percentile the. the 75 pecentile then subtract the numbers off from eachother.

Have an amazing day!

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A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 55 pounds each, and the small boxes

nikdorinn [45]

Answer:

The number of large boxes is 55 and the number of small boxes is 70

Step-by-step explanation:

The complete question is

A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 50 pounds each, and the small boxes weigh 20 pounds each. There are 125 boxes in all. If the truck is carrying a total of 4150 pounds in boxes, how many of each type of box is it carrying?

Let

x ------> the number of large boxes

y -----> the number of small boxes

we know that

$x+y=125$ -----> equation A

$50x+20y=4,150$ ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The intersection point is (55,70)

therefore

The number of large boxes is 55 and the number of small boxes is 70

3 0

2 years ago

Given cos(O)=3/5 and tan(O)

Valentin [98]

Answer:

Tan(O) = 4/3

Step-by-step explanation:

According to SOH CAH TOA

cos theta = adj/hyp

cosO = 3/4

adj = 3

hyp = 5

Get the opposite

Using pythagoras theorem

opp^2 = hyp^2-adj^2

opp^2 = 5^2 - 3^2

opp^2 = 25-9

opp^2 = 16

opp = 4

Tan (O) = opp/adj

Tan(O) = 4/3

Hence Tan(O) = 4/3

3 0

2 years ago

Wake up to reality

Sphinxa [80]

Answer:

What do I answer?.......

6 0

2 years ago

The unshaded area inside the figure to the right is 648 in.² Use this fact to write an equation involving x. Then solve the equa

FrozenT [24]

The second order polynomial that involves the variable x (border inside the rectangle) and associated to the unshaded area is x² - 62 · x + 232 = 0.

<h3>How to derive an expression for the area of an unshaded region of a rectangle</h3>

The area of a rectangle (A), in square inches, is equal to the product of its width (w), in inches, and its height (h), in inches. According to the figure, we have two proportional rectangles and we need to derive an expression that describes the value of the unshaded area.

If we know that A = 648 in², w = 22 - x and h = 40 - x, then the expression is derived below:

A = w · h

(22 - x) · (40 - x) = 648

40 · (22 - x) - x · (22 - x) = 648

880 - 40 · x - 22 · x + x² = 648

x² - 62 · x + 232 = 0

The second order polynomial that involves the variable x (border inside the rectangle) and associated to the unshaded area is x² - 62 · x + 232 = 0. $\blacksquare$