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yarga [219]
2 years ago
9

Multiply and verify the result when x=1,y=2 (Xy+xy^2 -1) (2x+3y)

Mathematics
2 answers:
Viktor [21]2 years ago
7 0
Sub in the values of X and Y
(1 * 2 + 1 * 2^2 - 1) (2 * 1 + 3 * 2)
PEMDAS. Everything is in parentheses so on to exponents. We have one. 2^2 = 4 so,
(1 * 2 + 1 * 4 - 1) (2 * 1 + 3 * 2)
Next, multiplication and division left to right.
(2 + 4 - 1) (2 + 6)
Addition and subtraction left to right.
(5) (8) or 5 * 8
Start PEMDAS over with the rest now that we’re outside of the original parentheses. No parentheses to navigate, no exponents left, multiplication and division. 5 * 8 = 40

Answer: 40
dezoksy [38]2 years ago
4 0

Step-by-step explanation:

please mark me as brainlest

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Instructions: Complete each question by choosing or typing in the best answer.
kupik [55]

The sum of 38 and twice a number x is 124. The value of "x" is 43

- 2x - 5 is equal to – 91.

<u>Solution:</u>

Given that , The sum of 38 and twice a number x is 124.  

We have to find what is - 2x - 5?

Now, according to given information, 38 + 2 × x = 124  

2x + 38 = 124  

2x = 124 – 38  

2x = 86  

x = 43

So, the value of x is 43

<em><u>Now, Evaluating - 2x – 5  </u></em>

Substitute "x" = 43 to evaluate

- 2(43) – 5  

- 86 – 5  = - 91

Hence, the required answer is – 91.

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