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ELEN [110]
2 years ago
8

here a subtraction problem that has been solved incorrectly for 21-9=11 choose the addition sentence that check this subtraction

problem what is the answer​
Mathematics
1 answer:
vitfil [10]2 years ago
6 0

Answer:

21-9 = 12

Step-by-step explanation:

I don't know if this is the correct sentence you are looking for though but i hope it helps

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Given f(x) = 7x-2, what is the value of f(2)?
motikmotik

Answer:

f(2)=12

Step-by-step explanation:

f(x)=7x-2

Plug 2 into the equation, since it says "f(2)".

f(x)=7(2)-2

f(x)=14-2

f(x)=12, done!

7 0
3 years ago
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A portion of the Quadratic Formula proof is shown. Fill in the missing statement. Statements Reasons x squared plus b over a tim
expeople1 [14]

Answer:

is this multiplication ?

Step-by-step explanation:

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3 years ago
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Find the slope of the line passing through the points (-9, -6) and [<br> (-4, 5)
lora16 [44]

Answer:

y2-y1         5--6            11

--------   =.  --------   =     ----

x2-x1         -4 --9           5

Step-by-step explanation:

3 0
3 years ago
A jar of peanut butter contains 454 g with a standard deviation of 10.2 g. Find the probability that a jar contains more than 46
Fofino [41]

Answer:

The probability that a jar contains more than 466 g is 0.119.

Step-by-step explanation:

We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.

Let X = <u><em>Amount of peanut butter in a jar</em></u>

The z-score probability distribution for the normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 454 g

           \sigma = standard deviation = 10.2 g

So, X ~ Normal(\mu=454 , \sigma^{2} = 10.2^{2})

Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)

            P(X > 466 g) = P( \frac{X-\mu}{\sigma} > \frac{466-454}{10.2} ) = P(Z > 1.18) = 1 - P(Z \leq 1.18)

                                                                  = 1 - 0.881 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

4 0
3 years ago
Select the expression that shows the application of the distributive property for
sergeinik [125]

Answer:

c. 9t+45 that shows distributive property

where it shows a*(b+c)=(a*b)+(b*c).so,9(t+5)=9*t+9*5

8 0
2 years ago
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