The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
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P(selecting a 10)= 4/52
P(selecting a 2)= 4/52
P(selecting a 4)=4/52
P(selecting an Ace)=4/52
P(selecting a diamond)=13/52
Answer:
17
Step-by-step explanation:
3^2+4^2-(4x2)
9+16-8
=17
Answer:
1.15x + 0.35x = 22.50
Step-by-step explanation:
Let x = number of days
If:
- DVD incurs an overdue fine of $1.15 per day
- book occurs an overdue fine of $0.35 per day
- total fine = $22.50
1.15x + 0.35x = 22.50
It is possible to prove that the right triangles are congruent through the right angle hypotenuse side theorem.