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slega [8]
2 years ago
7

Khan math homework due at 11 pm

Mathematics
2 answers:
salantis [7]2 years ago
3 0

Answer:

V=502.4

Step-by-step explanation:

3.14x4^2x10

Hope this helps :)

saul85 [17]2 years ago
3 0

Ignore this answer.

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A right triangle has a hypotenuse of 10 feet and a leg of 6 feet. What is the length of the other leg?
Artemon [7]

Answer:

The other length of the leg is <em>8 feet.</em>

Step-by-step explanation:

To find the answer we have to find what<em> 10</em> and <em>6 is squared.</em>  <em>10 x 10 = 100</em>.  

<em>6 x 6 = 36.  </em>Now since we are trying to find the length of the other leg, we will <em>subtract 100 from 36</em> and we get <em>64</em>.  Then for the last step, we will figure out what number<em> squared equals 64.</em>  Because 8 x 8 = 64, <em>8 is our answer.</em>

3 0
3 years ago
Pls help (ZOOM IN TO SEE FULL PIC)
Margarita [4]

Answer: 15

Step-by-step explanation:

Lets name the missing point as "x"

8^2 + x^2 = 17^2

=> 64 + x^2 = 289

=> x^2 = 289 - 64

=> x^2 = 225

=> x = 15

4 0
3 years ago
Right answers plzzzz
Andrew [12]
D.  

a. 

b. 

hope that helped
5 0
3 years ago
Read 2 more answers
An airplane is descending to a runaway. At an altitude of 15.2 miles, its horizontal distance to the runway is 60 miles. Find th
Snezhnost [94]

<u>Answer-</u>

<em>The angle of descent is 14.2 </em>

<em />

5 0
3 years ago
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
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