Khan math homework due at 11 pm

Mathematics

2 answers:

salantis [7]2 years ago

3 0

Answer:

V=502.4

Step-by-step explanation:

3.14x4^2x10

Hope this helps :)

saul85 [17]2 years ago

3 0

Ignore this answer.

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Prove whether or not the point (√21,2) lies on a circle centered at the origin and containing the point (5,0).

vesna_86 [32]

check the picture below.

so, we know the radius of this circle is 5 then, namely, the distance from (0,0) to (5,0) is 5.

now, if (√(21) , 2) indeed lies on that circle curve, then the distance from (0,0) to (√(21) , 2) will also be the same radius of 5 units.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{\textit{origin}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})}\qquad (\stackrel{x_2}{\sqrt{21}}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ r=\sqrt{(\sqrt{21}-0)^2+(2-0)^2}\implies r=\sqrt{(\sqrt{21})^2+2^2} \\\\\\ r=\sqrt{21+4}\implies r=\sqrt{25}\implies r=5~~~~\checkmark$