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Darya [45]
3 years ago
12

Jestions: 5

Mathematics
1 answer:
guapka [62]3 years ago
8 0

Answer:

I believe 2/7

Step-by-step explanation:

When you make them the same denominator they look like 48/84 > 24/84 and that's how you get the answer

You might be interested in
A camera shop purchases a camera for $56.98 and sells it for $102.56. What is the percent of markup?
Amiraneli [1.4K]

Answer:

180%

Step-by-step explanation:

Set up an equation:

Variable x = percent of markup

102.56/56.98 = x/100

Cross multiply

102.56 × 100 = 56.98 × x

10,256 = 56.98x

Divide both sides by 56.98:

179.99297.... = x

Round to nearest whole number:

180 = x

Check your work:

56.98 × 180%

Convert the percentage into a decimal:

56.98 × 1.80

102.564

Round to nearest cent:

102.56

Correct!

8 0
3 years ago
A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer
Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

L_A \to length of play area A

W_A \to width of play area A

L_B \to length of play area B

W_B \to width of play area B

x \to Area of A

y \to Area of B

From the question, we have the following:

L_A = 1 + 4W_A

W_B = 2 + W_A

L_B = 2 + 3W_B

x = y

The area of A is:

x = L_A * W_A

This gives:

x = (1 + 4W_A) * W_A

Open bracket

x = W_A + 4W_A^2

The area of B is:

y = L_B * W_B

y = (2 + 3W_B) * ( 2 + W_A)

Substitute: W_B = 2 + W_A

y = (2 + 3(2 + W_A)) * ( 2 + W_A)

Open brackets

y = (2 + 6 + 3W_A) * ( 2 + W_A)

y = (8 + 3W_A) * ( 2 + W_A)

Expand

y = 16 + 8W_A + 6W_A + 3W_A^2

y = 16 + 14W_A + 3W_A^2

We have that:

x = y

This gives:

W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2

Collect like terms

4W_A^2 - 3W_A^2 + W_A  -14W_A  - 16 =0

W_A^2  -13W_A  - 16 =0

Using quadratic calculator, we have:

W_A = -14.1 or W = 1.13 --- approximated

But the width can not be negative; So:

W = 1.19

7 0
3 years ago
Which point is on the graph of f(x) = 2*5^x
vodomira [7]

Answer:

Option B (1,10)

Step-by-step explanation:

we have

f(x)=2(5^x)

we know that

If a ordered pair is on the graph of f(x) then the ordered pair must satisfy the function f(x)

<u><em>Verify each case</em></u>

case A) (0,0)

For x=0

f(x)=2(5^0)\\f(x)=2(1)=2

Compare the value of f(x) with the y-coordinate of the ordered pair

2\neq 0

therefore

The ordered pair is not on the graph of f(x)

case B) (1,10)

For x=1

f(x)=2(5^1)\\f(x)=2(5)=10    

Compare the value of f(x) with the y-coordinate of the ordered pair

10=10

therefore

The ordered pair is on the graph of f(x)

case C) (0,10)

For x=0

f(x)=2(5^0)\\f(x)=2(1)=2

Compare the value of f(x) with the y-coordinate of the ordered pair

2\neq 10

therefore

The ordered pair is not on the graph of f(x)

case D) (10,1)

For x=10

f(x)=2(5^{10})\\f(x)=2(9,765,625)=19,531,250

Compare the value of f(x) with the y-coordinate of the ordered pair

19,531,250\neq 1

therefore

The ordered pair is not on the graph of f(x)

7 0
4 years ago
QUICK HELP!!!!!!!!!!!!!!!!
JulijaS [17]

Answer:

Its C im pretty sure. Also loveee your pfp!

3 0
3 years ago
PLEASE HELP ME ASAP
goblinko [34]

Answer:

20.04 units

Step-by-step explanation:

The diagram shows right triangle ABC. Use the definition of the cosine:

\cos \angle C=\dfrac{\text{Adjacent leg}}{\text{Hypotenuse}}\\ \\\cos \angle C=\dfrac{BC}{AC}\\ \\\cos 51^{\circ}=\dfrac{BC}{27}\\ \\BC=27\cdot \cos 51^{\circ}\\ \\BC\approx 20.04\ units

3 0
4 years ago
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