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slava [35]
2 years ago
9

At Garland School,

Mathematics
1 answer:
ankoles [38]2 years ago
8 0

490 x 2/5 = 980/5 = 196 girls at Garland


945 x 5/7 = 4725/7 = 675 girls at Bowood


Bowood has more girls:

675-196 = 479 more

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Jlenok [28]
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3 years ago
Which expression can be used to find 57% of 230? ⊥ω⊥
ella [17]

Answer:

131.10  (Answer C)

Step-by-step explanation:

Convert 57% to 0.57 and then multiply 230 by 0.57:

0.57(230) = 131.10

This is Answer C

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Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
2 years ago
Solve the one-step equation <br> -9 = u/-6
sladkih [1.3K]

Answer:

3

Step-by-step explanation:

-6 x 3 = -9

4 0
2 years ago
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