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ololo11 [35]
2 years ago
5

A guest walks in and needs a room for the night. The rack rate for rooms is 15% higher than the average rate of $165 per night.

What rate will the walk-in guest pay for the night?
Mathematics
1 answer:
Vikentia [17]2 years ago
7 0

The rate which the walk-in guest is how fast a guest needs a room

The rate which the walk-in guest pay for the night is $189.75

<h3>How to determine the rate?</h3>

The given parameters are:

Average rate = $165 per night

The walk-in guest is 15% greater than the average rate.

So, the rate of the walk-in guest is:

Walk-in = 165 * (1 + 15%)

Evaluate the product

Walk-in = $189.75

Hence, the rate which the walk-in guest pay for the night is $189.75

Read more about rates at:

brainly.com/question/8728504

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If each student needs 1/3 of a stick of clay to do an art project,and there are 4 sticks of clay, how many students can do the a
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5) Find the area of a rectangle<br> with points at (-8,5), (2,5),<br> (2,-3) and (-8,-3).
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Answer:

80 units²

Step-by-step explanation:

Given <u>vertices</u> of a rectangle:

  • A = (-8, 5)
  • B = (2, 5)
  • C = (2, -3)
  • D = (-8, -3)

As points A and D share the <u>same x-coordinate</u>, and points B and C share the <u>same x-coordinate</u>, the difference between the different <u>x-coordinates</u> is the length of the rectangle:

\begin{aligned}\implies \textsf{Length} & = x_B-x_A\\& = 2-(-8)\\& = 2+8\\& = 10\; \sf units\end{aligned}

As points A and B share the <u>same y-coordinate</u>, and points C and D share the <u>same y-coordinate</u>, the difference between the different <u>y-coordinates</u> is the width of the rectangle:

\begin{aligned}\implies \textsf{Width} & = y_A-y_D\\& = 5-(-3)\\& = 5+3\\& = 8\; \sf units\end{aligned}

Therefore:

\begin{aligned}\textsf{Area of a rectangle} & = \sf width \times length\\&=8 \times 10\\&=80 \sf \; units^2\end{aligned}

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