Answer:
in the pic
Step-by-step explanation:
answer A
.....
Answer:
4
Step-by-step explanation:
2*6 = 12
3*4 =12
these are all the numbers that would be a factor of 12 between 2-10
The inequality
gives the least number of buses, b, needed for the trip. The least number of buses is 9
<u>Solution:</u>
Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.
Each bus can seat a maximum of 48.
We have to find which inequality gives the least number of buses, b, needed for the trip?
Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers
<em><u>The number of buses required “b” is given as:</u></em>


Number of buses required ≥ 9 buses.
But least number will be 9 from the above inequality.
Hence, the inequality
gives least count of busses and least count is 9.
Answer:
34
explanation:
First of all, put the numbers in order
30, 31, 31, 32, 33, 35, 35, 35, 36, 36
Then, find the middle number.
In this case, there is an even amount of numbers so, we have to pick the 2 middle numbers which is 33 and 35.
Now all you have to do is add these two numbers together then divide by 2 which will give you 34.
or, in simpler questions like this one, you can just say 34 as you know it is between 33 and 35.
In other questions, it might have and odd amount of numbers, for example:
3, 3, 5, 8, 10
so all you would do here is pick the middle number which would be 5. (it has 2 numbers on each side of it)
Answer:
0.75
Step-by-step explanation:
Given,
P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,
P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,
Where,
A = event that the selected student has a Visa card,
B = event that the selected student has a MasterCard,
C = event that the selected student has an American Express card,
We know that,
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07
= 0.75
Hence, the probability that the selected student has at least one of the three types of cards is 0.75.