I need help...you will be mark brainliest if it's right ty

You(or your parents) earn$53,698.00/yr and you have deductions of FICA(7.65%), federal tax withholding(11.5%), and state tax wit

anyanavicka [17]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

net income is 38582.01 for the year/12 = 3215.17(rounded) per month
since rent/mortgage should not exceed 25% of income, that is about 800/month

4 0

3 years ago

Please answer this question, and happy valentines day!! <3

tino4ka555 [31]

Given:

The two ways table.

To find:

The number of girls in year 9.

Solution:

Using the two ways table, we get

Boys in year 10 = Total student in year 10 - Girls in year 10

= 256 - 123

= 133

Boys in year 9 = Total boys - Boys in year 10 - Boys in year 11

= 407 - 133 - 125

= 149

Girls in year 9 = Total students in year 9 - Boys in year 9

= 303 - 149

= 154

Therefore, the number of girls in year 9 is 154 and the correct option is C.

6 0

3 years ago

What is the length of CD in this diagram, ABC - EDC,

natima [27]

Answer:

Option A is the right option.

solution,

∆ABC~∆EDC

$\frac{bc}{cd} = \frac{ac}{ec} \\ \:$

putting the values,

$\frac{20 - x}{x} = \frac{20}{5} \\ or \: 5(20 - x) = 20x(cross \: multiplication) \\ or \: 100 - 5x = 20x \\ or \: - 5x - 20x = - 100 \\ or \: \: - 25x = - 100 \\ \: or \: x = \frac{ - 100}{ - 25} \\ x = 4$

Hope this helps..

Good luck on your assignment..

8 0

3 years ago

Read 2 more answers

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

1. Which is larger, a+c or b+d?

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, add "a-b" (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (the additive identity) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and "a-b" is positive...

$(a-b)+(c-d) > a-b > 0$

... so, by the transitive property of inequality...

$(a-b)+(c-d) > 0$

Recall that subtraction is addition by a negative number...
$a+(-b)+c+(-d) > 0$

...and that addition is associative and commutative, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

Adding b + d to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and simplifying

$a+c > b+d$

So, a+c is larger than b+d.

2. Which is larger, a+d or b+c?

Consider the following two examples:

Example 1

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

Example 2

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0

2 years ago

The area of a rectangle is 45 cm2. Two squares are constructed such that two adjacent sides of the rectangle are each also the s

lorasvet [3.4K]

Answer:

The length of sides of one square is 5cm and length of sides of another square is 9cm

Step-by-step explanation:

Let the length of rectangle be x and width of rectangle be y.

We have given,

Area of rectangle = 45 cm²

i.e. Area of rectangle = x·y = 45 or xy = 45 ---------(1)

Next, two squares are constructed from two adjacent sides of rectangle.