All categories

2 years ago

Can someone please help me find the ordered pairs for U and T? thanks!

Mathematics

1 answer:

LiRa [457]2 years ago

8 0

u (-1 ; 0)

t (-3 ; 0)

You might be interested in

Choose the numerical expression that represents multiplying the sum of 159 and 833 by 6

Eva8 [605]

Answer:

(159+833)*6 = 5952

Step-by-step explanation:

(159 + 833) * 6

= 992*6 = 5952

4 0

3 years ago

PLEASE HELPPPPPPPPPPPPPPPPPPPPP

astra-53 [7]

Answer:

348

Step-by-step explanation:

Length-l

Width-w

Height-h

A=2(wl+hl+hw)=2·(8·9+6·9+6·8)=348

3 0

3 years ago

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago

Use the following problem to answer the question below:

Rom4ik [11]

Answer:

m∠ABD = m∠CBE ⇒ by subtracting a common angle from the given angles

Step-by-step explanation:

∵ m∠ABE = m∠CBD

∵ m∠ABD = m∠ABD + m∠DBE

∵ m∠CBD = m∠CBE + m∠EBD

∵ ∠EBD is common angle between them

∴ m∠ABD = m∠CBE

6 0

3 years ago

If the cash price of a truck is $25,000 and a business

olasank [31]

Answer:

500$

finaced= provide funding for

5 0

3 years ago