Can someone please help me find the ordered pairs for U and T?<br><br> thanks!

What is the justification for step 1 in the solution process?

Sholpan [36]

It’s the subtraction property of equality because you’re subtracting 15 from both sides

7 0

2 years ago

PLZ ANSWER WILL MARK BRAINLIST 3O POINTS!!!!! How do you calculate the residuals for a scatterplot?

Vikki [24]

Answer:

So, to find the residual I would subtract the predicted value from the measured value so for x-value 1 the residual would be 2 - 2.6 = -0.6.

Step-by-step explanation:

4 0

2 years ago

Polimerlerin su ile parçalanarak monomerlerine ayrılmasına ne denir?<br>

kolbaska11 [484]

Answer:

tarlak iefdiebdid didbdkd

5 0

2 years ago

A roulette wheel has 38 3838 slots, of which 18 1818 are red, 18 1818 are black, and 2 22 are green. In each round of the game,

Elina [12.6K]

The value of P(R = 3) is 0.2854

<h3>Probability</h3>

Probabilities are used to determine the chances of events.

The given parameters are:

$n = 38$ --- the number of slots
$red = 18$ . --- the number of red slot
$black = 18$ . --- the number of black slot
$green = 2$ . --- the number of green slot

<h3>Individual probabilities</h3>

The probability that the ball lands on a red slot is calculated as:

$p = \frac{18}{38}$

Simplify

$p= \frac{9}{19}$

The probability that the ball does not land on a red slot is calculated as:

$q = \frac{18+2}{38}$

$q = \frac{20}{38}$

Simplify

$q = \frac{10}{19}$

<h3>Binomial probability</h3>

The value of P(R = 3) is then calculated using the following binomial probability formula

$P(R = r) = ^nC_rp^rq^{n-r}$

Where:

$n = 7$

$r = 3$

So, we have:

$P(R = 3) = ^7C_3 \times (9/19)^3 \times (10/19)^{7-3}$

$P(R = 3) = 35 \times (9/19)^3 \times (10/19)^4$

$P(R = 3) = 0.2854$

Hence, the value of P(R = 3) is 0.2854

Read more about probabilities at:

brainly.com/question/15246027

8 0

2 years ago

Read 2 more answers

Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north

Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

$x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]$

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

Child 1 final position => $x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t$
Child 2 final position => $x_{2f} =0+v_{2} t$

4) Sum the equations and equate to 3

$x_{1f} +x_{2f} =3$

5) Substitute the values we already know

$1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]$

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0

2 years ago

Can someone please help me find the ordered pairs for U and T? thanks!