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2 years ago

What is the solution of this equation -12x-7=53

Mathematics

2 answers:

umka21 [38]2 years ago

8 0

Answer:

<em>x </em>= -5

Step-by-step explanation:

You have to work backwards.

53 + 7 = 60

60 ÷ 12 = 5

Add the negative »»» -5

Taya2010 [7]2 years ago

5 0

X= -5

Explanation: Move the constant to the right-hand side and change its sign, Add the numbers, Divide both sides of the equation by -12.

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Riya took a train from his hometown to Mumbai . The journey lasted for 3 hrs 35 minutes . The train reached the station at 9:15

zhenek [66]

Answer: 5:40 am

Step-by-step explanation:

The train reached the station at 9:15 am after having travelled for 3 hrs 35 minutes.

The time the train departed from Riya's hometown was the time it arrived in Mumbai station less the time taken to travel:

= 9:15 - 3:35

First deduct the 3 hours:

= 9:15 - 3

= 6 : 15 am

Remove the 35 minutes by first removing the 15 minutes

= 6:15 - 15

= 6:00 am

Then remove the rest of the 35 minutes which is 20 minutes:

= 6:00 - 20 minutes

= 5:40 am

7 0

2 years ago

Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=

Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = $x^2 + y^2 +z^2 = 4^2$

$z^2 = 16 -x^2 -y^2$

$z = \sqrt{16-x^2-y^2}$

The partial derivatives of $Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}$

$Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}$

Similarly;

$Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}$

∴

$dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA$

$=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA$

$=\sqrt{ \dfrac{16}{16-x^2-y^2} }\ \ .dA$

$=\dfrac{4}{\sqrt{ 16-x^2-y^2} }\ \ .dA$

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to $\sqrt{12}$

dA = rdrdθ

∴

The surface area $S = \int \limits _R \int \ dS$

$= \int \limits _R\int \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA$

$= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \ \ rdrd \theta$

$= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr$

$= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}$

$= 8\pi ( - \sqrt{4} + \sqrt{16})$

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0

3 years ago

Estimate the sum of 279 and 217

Maurinko [17]

280+220=500 hope this helps

7 0

3 years ago

The table of values represents a linear function g(x), where x is the number of days that have passed and g(x) is the balance in

katovenus [111]

Answer:

Here is your answer

Step-by-step explanation:

3 0

2 years ago

Geoff has a bag that contains 4 red marbles and 6 blue marbles. He chooses two marbles at random and does not replace them. What

posledela

Total number of marbles = 10

Number of red marbles = 4

Number of blue marbles = 6

Probability = $\frac{number of favorable outcomes}{total number of outcomes}$

The probability that the first marble is blue = $\frac{6}{10}$

The probability that the first marble is red = $\frac{4}{9}$ ; 9 because 1 marble has already been taken out.

Joint probability= probability of event A * Probability of event B

= $\frac{6}{10}\times\frac{4}{9}$ = $\frac{24}{90}= \frac{4}{15}$

3 0

3 years ago